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Harrizon [31]
3 years ago
6

If a number has an infinite amount of 0's on the end of it, can I shorten it to just one 0?

Mathematics
1 answer:
Alex777 [14]3 years ago
7 0

yea just put a line over the 0 to indicate it's infinite

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(x+3)(x-5)-(4x+1)(1-4x)=17x^
Greeley [361]

Answer: \boxed{Sol=\{\dfrac{7}{4} \}}\\

I suppose 17x^ means 17x².

and that we must solve the equation.

Step-by-step explanation:

(x-3)(x-5)-(4x+1)(1-4x)=14x^2\\\\x^2-3x-5x+15+(4x+1)(4x-1)=17x^2\\\\x^2-8x+15+16x^2-1=17x^2\\\\-8x+14=0\\\\8x=14\\\\x=\dfrac{7}{4} \\\\\boxed{Sol=\{\dfrac{7}{4} \}}\\

6 0
3 years ago
Need help desperately T~T
babunello [35]
As you can see, angle 5 and angle 6 are supplementary.  And angle 5 and angle 3 are congruent because they are alternate interior angles.  

So it will be
x+2 = 180- x+3 
                         move x over from the right to the left
2x+2 = 183
                         move 2 over from the left to the right
2x = 181
                          divide by 2
x= 90.5

and angle 3 and angle 1 are vertical angles so they are congruent.  Using the angle 3 formula to solve for the answer:

90.5+3 =93.5

When angles are congruent, their measures are congruent, therefore, measure of angle 1 is 93.5
4 0
3 years ago
What is the range of possible sizes for side x
vladimir1956 [14]

Answer:

4<x<12

Step-by-step explanation:

8.0+4.0=12.0

8.0-4.0=4.0 or 4

5 0
2 years ago
Read 2 more answers
Please help answer these questions
vfiekz [6]

<u>Step</u><u> </u><u>1</u>

given

<u>Step</u><u> </u><u>2</u>

\angle HKM \cong \angle OKM, \angle HMK \cong \angle OMK

<u>Step</u><u> </u><u>3</u>

\overline{KM} \cong \overline{KM}

Reason: Reflexive property

<u>Step</u><u> </u><u>4</u>

ASA

8 0
2 years ago
Quadrilateral ABCD is a square. if m
olganol [36]
The answer is B. 18

Explanation:

We know that a square has 4 right angles. A right angle is 90°.

5x° = 90°
5(18)° =90°
90°=90°

Hope this helps some
4 0
3 years ago
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