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3 years ago

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You started on a bike trip, riding at a rate of 9 miles per hour. Your friend left one hour later and rode at the rate of 12 mil

es per hour. How long did it take your friend to catch up with you?

1 answer:

Ne4ueva [31]3 years ago

6 0

<span>You're 9 miles ahead when the 2nd bike starts.
His speed wrt you is 3 mph (12-9).
9/3 = 3 hours
I hope i helped you
</span>

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Find the magnitude of WX for W(-2, 8, -3) and X(1, 4, -1)

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Step-by-step explanation:

The magnitude of XY (its length) where,

$X=(x_{1},y_{1},z_{1})$
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is IXYI = $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}+(z_{2}-z_{1})^{2}}$

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∵ X = (1 , 4 , -1)

- To find the magnitude of WX use the formula above

∴ $x_{1}$ = -2 and $x_{2}$ = 1

∴ $y_{1}$ = 8 and $y_{2}$ = 4

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- Substitute these values in the rule above

∵ IWXI = $\sqrt{(1--2)^{2}+(4-8)^{2}+(-1--3)^{2}}=\sqrt{9+16+4}$

∴ IWXI = $\sqrt{29}$

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