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3 years ago

What is the answer to my problem

Mathematics

2 answers:

valina [46]3 years ago

8 0

95.3 because 95.25 rounded is 95.3

mina [271]3 years ago

5 0

95.25

The 5 get rounded up into the 2 making it a three equaling 95.3 or 95.30

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Please help! 50 POINTS!!!

expeople1 [14]

Answer:

f(x) = 2/3 x +3

Step-by-step explanation:

We know the y intercept ( where it crosses the y axis) is 3

We can calculate the slope from 2 points (-3,1) and (0,3)

Slope = (y2-y1)/(x2-x1)

= (3-1)/(0--3)

= (3-1)/(0+3)

= (2/3)

The slope is 2/3

Since we know the slope and the y intercept, we can use the slope intercept form

y= mx+b

y = 2/3 x+3

f(x) = 2/3 x +3

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3 years ago

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What is the point of intersection of the x-axis and the y-axis called

tester [92]

That is called the Origin , where the number 0 is.

6 0

3 years ago

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2/3 – 2/6<br> write answer as a fraction

lisabon 2012 [21]

Answer:

It's 1/3

Step-by-step explanation:

2/6 is equivalent to 1/3, so you can rewrite the question as 2/3 - 1/3.

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3 years ago

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In 2006 Edison, NJ had a population of 100,500. Livermore, CA had a population of 78,400. What was the total population of these

forsale [732]

The answer is simple:
Just add the two populations together.

100,500 + 78,400 = 178,900

ANSWER: A. 178,900

Hope this helps! Have a good night and God bless (:

7 0

4 years ago

Please help ASAP! Thanks! For the figures below, assume they are made of semicircles, quarter circles and squares. For each shap

bazaltina [42]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)$

$A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

<em>The circumference of a quarter of circle is equal to</em>

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)$

$C=6\pi\ cm$

The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)

$AC=\sqrt{12^2+12^2}$

$AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

6 0

3 years ago