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serious [3.7K]
2 years ago
14

Police use the formula [math]v=2 \sqrt{5 L}[/math] to estimate the speed of a car, v, in miles per hour, based on the length, L,

in feet, of its skid marks upon sudden braking on a dry asphalt road. A motorist is involved in an accident. A police officer measures the car’s skid marks to be 45 feet long. Estimate the speed at which the motorist was traveling before braking. If the posted speed limit is 35 miles per hour and the motorist tells the officer she was not speeding, should the officer believe her? Explain
Mathematics
1 answer:
Len [333]2 years ago
8 0

Answer:

V(L=45) = 2\sqrt{5*45ft}= 2 \sqrt{225}= 2*15 =30 \frac{mi}{hr}

And if we compare this value with the speed limit of 35 mi/h then the police officer should believe that the motorist was not speeding, since his speed was lower than 35 mi/hr.

Step-by-step explanation:

Estimate the speed at which the motorist was traveling before braking

For this case we have the following formula for the spped of a car:

V= 2 \sqrt{5L}

Where L represent the length and v the velocity in miles/hr.

For this case we know that a police officer measures the car’s skid marks to be 45 feet long, so then L =45 ft, and we can finde the velocity of the car replacing L=45 ft and we got:

V(L=45) = 2\sqrt{5*45ft}= 2 \sqrt{225}= 2*15 =30 \frac{mi}{hr}

If the posted speed limit is 35 miles per hour and the motorist tells the officer she was not speeding, should the officer believe her? Explain

And if we compare this value with the speed limit of 35 mi/h then the police officer should believe that the motorist was not speeding, since his speed was lower than 35 mi/hr.

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the correlation between two variables related to the same sample is a scaled quantitative measure. what is used to scale this me
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Any statistical relationship between two random variables or bivariate data, whether causal or not, is referred to in statistics as correlation or dependence.

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In order to scale the measurement between two variables connected to a similar sample, the standard deviation measures dispersion.

The variables' standard deviations are the best choice as a result.

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Option involving the coefficients of variation of two variables is incorrect because the coefficient expressing standard deviation and mean ratio determines how much variation there is.

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Hence, the correct option is the standard deviations of the variables.

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Complete question:

The correlation between two variables related to the same sample is a scaled quantitative measure. What is used to scale this measurement?

- the standard deviations of the variables

- the standard errors of the variables

- the coefficients of variation of the two variables

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Bethany purchased gasoline at four different gas stations. The table shows the total cost of the gasoline she
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(c) Use a calculator to verify that Σ(x) = 64, Σ(x2) = 1118, Σ(y) = 628, Σ(y2) = 87,982, and Σ(x y) = 9,627.
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The correlation based on the computation is 0.97.

<h3>How to compute the value?</h3>

It should be noted that the question is that we should simply calculate the correlation which is r.

The correlation will be:

= Σ(x y) / (Σ(x²) × Σ(y²)

= 9627/✓(1118 × 87982)

= 9627 ✓98363876

= 9627/9917.86

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Determine the domain of the function, and then graph it.
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