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3 years ago

What is asked on algebra basics DBA for flvs

Mathematics

1 answer:

stich3 [128]3 years ago

6 0

Answer:

Everything in your lesson depending on what your doing it could be from vocab definitions to various questions. It honestly depends on what class(es) you are taking.

Step-by-step explanation:

You might be interested in

What form is this equation in y= -3(x-5)^2+7 in?

Marianna [84]

Answer:

vertex form

Step-by-step explanation:

y= -3(x-5)^2+7

This equation is written in vertex form

y = a(x-h)^2 +k

The vertex is (h,k)

8 0

4 years ago

Read 2 more answers

Write the slope-intercept form of the equation that passes through the point (1,5) and is perpendicular to the line y =-x + 3

Diano4ka-milaya [45]

Answer:

y = -1/7x - 23/7

Step-by-step explanation:

Step 1: Find slope m

m = (-4 + 3)/(5 + 2)

m = -1/7

y = -1/7x + b

Step 2: Find b

-3 = -1/7(-2) + b

-3 = 2/7 + b

b = -23/7

Step 3: Rewrite equation

y = -1/7x - 23/7

4 0

4 years ago

??????????????????????

Leviafan [203]

√(x + 9) - 4 = 1
√(x + 9) - 4 (+4) = 1 (+4)
√(x + 9)(²) = 5(²)
x + 9(-9) = 25(-9)
x = 16

hope this helps

6 0

4 years ago

Simplest form for 4 1/10

Hunter-Best [27]

Answer:

That is the simplest form.

Step-by-step explanation:

6 0

3 years ago

Given point T(-6,-3) and point K(2,3), find the distance from point T to point K.

navik [9.2K]

Answer:

$d = 10$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra II

Distance Formula: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point T (-6, -3)

Point K (2, 3)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute [DF]: $d = \sqrt{(2+6)^2+(3+3)^2}$
Add: $d = \sqrt{(8)^2+(6)^2}$
Exponents: $d = \sqrt{64+36}$
Add: $d = \sqrt{100}$
Evaluate: $d = 10$

7 0

3 years ago