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murzikaleks [220]

3 years ago

7

Find the mean and the median of the data set..... 200,167,185,212,195,193,188,140

1 answer:

astraxan [27]3 years ago

4 0

You Will Add Up All The Number Then Divide By The Total Number You Have In All
The Mean Is 185
You Put All The Number In Order For The Median
140,167,185,188,193,195,200,212
So You Have Two Number Which Are 188 and 195
You Will Add 188 + 195=383
Now You Divide 383 By 2 Which Is 191.5

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Step-by-step explanation:

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1 year ago

ANSWER FOR BRAINILEST.

Lesechka [4]

Answer:

2713

Step-by-step explanation:

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3 years ago

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mojhsa [17]

<h2>Answer:</h2>

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<u>#9:</u>

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7 0

3 years ago

1 point) Are the functions f,g, and h given below linearly independent? f(x)=e3x+cos(5x), g(x)=e3x−cos(5x), h(x)=cos(5x). If the

Fynjy0 [20]

Answer:

Functions are linearly dependent (are not linearly independent.)

Step-by-step explanation:

Remember that two functions f(x), g(x) and h(x) are said linearly independent on an interval I if the <em>only solution</em> to the equation

$\alpha f(x)+\beta g(x)+\omega h(x)=0, \ \text{for all } x\in I$

is the trivial one: α = 0, β = 0, ω = 0. If they are not linearly independent, they are called linearly dependent.

Now, let f(x), g(x) and h(x) be the functions:

$f(x)=e^{3x}+\cos(5x),$

$g(x)=e^{3x}-\cos(5x),$

$h(x)=\cos(5x).$

Then, letting α = 1, β= -1 and ω = -2, we see that:

$\alpha f(x)+\beta g(x)+ \omega h(x)=e^{3x}+\cos(5x)-e^{3x}+\cos(5x)+2\cos(5x)=0.$

Hence, the functions f(x), g(x) and h(x) are not linearly independent, or equivalently, are linearly dependent.

8 0

3 years ago