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GrogVix [38]
3 years ago
14

If you know the circumstance of a circle, which step(s) can you follow to find its diameter?

Mathematics
1 answer:
Oxana [17]3 years ago
5 0

Answer:

B

Step-by-step explanation:

This is the correct answer ;)

If the circumference of a circle was, for example, 25, to find the diameter, well have to divide 25 from pie to get it.

The answer would've been <em>7.957747</em><em>.</em><em> </em>

Therefore B is the right answer :)

<em>PLEASE</em><em> </em><em>DO MARK</em><em> </em><em>ME AS</em><em> </em><em>BRAINLIEST</em><em> </em><em>IF</em><em> </em><em>MY</em><em> </em><em>ANSWER IS</em><em> </em><em>HELPFUL</em><em> </em>

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Please help!! Write in simplest radical form: √7/8 Show how you figured it out
12345 [234]

Given expression: \sqrt{\frac{7}{8}}.

\mathrm{Apply\:radical\:rule\:}\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}

=\frac{\sqrt{7}}{\sqrt{8}}

\sqrt{8}=\sqrt{2^2\cdot \:2}=2\sqrt{2}

\frac{\sqrt{7}}{\sqrt{8}} =\frac{\sqrt{7}}{2\sqrt{2}}

\mathrm{Rationalize\:}\frac{\sqrt{7}}{2\sqrt{2}}

\mathrm{Multiply\:by\:the\:conjugate}\:\frac{\sqrt{2}}{\sqrt{2}}

=\frac{\sqrt{7}\sqrt{2}}{2\sqrt{2}\sqrt{2}}

=\frac{\sqrt{14}}{4}

=\frac{\sqrt{14}}{4}.

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4 years ago
What is 16% of 43 minutes
Genrish500 [490]
6.88 i hope this helps u
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3 years ago
Read 2 more answers
Α' β
yulyashka [42]

Answer:

8x² +36x -27=0

Step-by-step explanation:

2x²= 6x +3

Let's rewrite the equation into the form of ax²+bx+c= 0.

2x² -6x -3=0

Thus, a= 2

b= -6

c= -3

Sum of roots= -  \frac{b}{a}

Since your roots are p and q, sum of roots= p +q

p +q= - (\frac{ - 6}{2} )

p +q= 6 ÷2

p +q= 3

Product of roots= \frac{c}{a}

pq= -  \frac{3}{2}

<u>Quadratic equations</u><u>:</u>

x² -(sum of roots)x +(product of roots)= 0

Thus, we have to find the sum and the product of the new roots, p²q and pq².

p +q= 3

pq= -3/2

Product of new roots

= (p²q)(pq²)

= p³q³

= (pq)³

= ( -  \frac{3}{2} )^{3}  \\  =  -  \frac{27}{8}

sum of new roots

= p²q +pq²

= pq(p +q)

= (-3/2)(3)

= -9/2

Thus, the quadratic equation with roots p²q and pq² is

x² -(-9/2)x -27/8 = 0

x ^{2}  +  \frac{9}{2} x -  \frac{27}{8}  = 0

Multiply by 8 throughout:

8 {x}^{2}  + 36x - 27 = 0

3 0
3 years ago
Twice x increased by five is 27. What is x?
Flauer [41]

Answer:

x=11

Step-by-step explanation:

2x+5=27

2x=22

x=11

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3 years ago
What kind of financial institutions does the Office of Thrift Supervision oversee?
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Savings and Loan Institutions.
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