8 • 6 = 48 cards total
48 ÷ 3 = 16 cards per person
From the given mean and margin of error, the 99% confidence interval for the mean amount of money spent on lunch per week for all students is:
[$19.5, $22.5].
<h3>How to calculate a confidence interval given the sample mean and the margin of error?</h3>
The confidence interval is given by the sample mean plus/minus the margin of error, hence:
- The lower bound is the sample mean subtracted by the margin of error.
- The upper bound is the sample mean added to the margin of error.
For this problem, we have that:
- The sample mean is of $21.
- The margin of error is of $1.50.
Hence the bounds are given as follows:
- Lower bound: 21 - 1.50 = $19.50.
- Upper bound: 21 + 1.50 = $22.50.
Hence the interval is [$19.50, $22.50].
More can be learned about confidence intervals at brainly.com/question/25890103
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Answer:
FIRST ONE
Step-by-step explanation:
Di you leave out some parenthesis? This looks like 3x+17x+53, which is the same as 20x+53? That is not enough information to solve. however, if you meant one angle was 3x+17 and the other was x+53, just set the two equal to each other to solve for x, then plug that into one of the equations to find the measurement of the angle.
This is because
(that is, replace any instance of <em>x</em> in the definition of <em>g</em> with √<em>x</em> )
and
(replace any <em>x</em> in <em>f</em> with √<em>x</em> - 1)
Also acceptable:
(assuming <em>x</em> is not negative)
