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JulsSmile [24]
3 years ago
13

Help me please please

Mathematics
1 answer:
lilavasa [31]3 years ago
5 0

Answer triangle RST is congruent to the triangle LMK

If you move the triangle vertically you can find the congruency of two sides and one angle

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Which of the following equations shows how substitution can be used to solve
maxonik [38]

Answer:  Choice B)

2x+5(2x+3) = 3

============================================

Reasoning:

We start with the second equation 2x+5y = 3

Since y = 2x+3 from the first equation, we can replace every copy of y with (2x+3). This replacement is valid because y and 2x+3 are the same.

So that's how we go from 2x+5y = 3 to 2x+5(2x+3) = 3

This replacement is done to get rid of the y variable, and it allows us to solve for x later on.

3 0
3 years ago
Please help me with this
kupik [55]

Answer:

–x² + 12x + 5

Step-by-step explanation:

x² + 3x

–2x² + 9x + 5

The sum of the above expression can be obtained as follow:

.... x² + 3x

+ –2x² + 9x + 5

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

–x² + 12x + 5

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

Thus, the sum of x² + 3x and –2x² + 9x + 5 is –x² + 12x + 5

3 0
3 years ago
There are 400 students in a school. Fifty five percent are girls. How many boys are there?
ki77a [65]
1) 55% is girls, then 
100-55=45% is boys.

2) 45%=0.45                                     or  2) 400 ----100%
3)400*0.45= 180 boys                                 x -----45%      x=400*45/100=180 boys

Answer is 180 boys.
5 0
3 years ago
How to solve -8+squre root (5a-5)=-3
sertanlavr [38]

Answer:

a=6

Step-by-step explanation:

Given equation:

-8+\sqrt{5a-5}=-3

Solving for unknown variable a

Adding 8 both sides by additive property of equality.

+8-8+\sqrt{5a-5}=-3+8

\sqrt{5a-5}=5

Squaring both sides to remove the square root.

(\sqrt{5a-5})^2=5^2

5a-5=25

Adding 5 both sides by additive property of equality.

5a-5+5=25+5

5a=30

Dividing both sides by 6 to isolate a

\frac{5a}{5}=\frac{30}{5}

∴ a=6

8 0
3 years ago
Kierston needs to paint a wall of the youth center. She knows that 1 can of paint covers an area of 2.2 square meters. Kierston
Step2247 [10]

Answer:

See Explanation

Step-by-step explanation:

Given

1\ can = 2.2m^2

Required

Determine the number of cans for the wall

The dimension of the wall is not given. So, I will use the following assumed values:

Length=20m

Width = 44m

First, calculate the area of the wall

Area = Length * Width

Area = 20m * 44m

Area = 880m^2

If 1\ can = 2.2m^2

Then x = 880m^2

Cross Multiply:

x * 2.2m^2 = 1 * 880m^2

x * 2.2m^2 = 880m^2

x * 2.2 = 880

Make x the subject

x = \frac{880}{2.2}

x = 400

400 cans using the assume dimensions.

So, all you need to to is, get the original values and follow the same steps

4 0
3 years ago
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