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sertanlavr [38]
3 years ago
8

In the typing world, 80 words per 5 minutes is considered acceptable.

Mathematics
2 answers:
harkovskaia [24]3 years ago
8 0

Answer:

16

Step-by-step explanation:

Anastaziya [24]3 years ago
5 0

Answer:

16

Step-by-step explanation:

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a team played 18 games during the season. the team lost 8 games and won the rest. what is the ratio of wins to losses
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8 out of 18 games. That 8/18 simplify to 4/9 ?

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Match the mean mode median and range for data set below 7,3,7,7,8,6,7,3
solniwko [45]

Answer:

mean is 6 mode is 7 range is 5 median is 7.5

Step-by-step explanation:

mean add all numbers divide by 8

mode is most shown number

range is 8-3

median out numbers in order if the numbers counted even you should have a decimal point

5 0
3 years ago
Triangle ABC has verticles A(0,6), B(-8, -2), and C(8,-2). A dilation with a scale factor of 1/2
FromTheMoon [43]
Multiply x and y by 1/2(0.5)

-8 × 1/2 = -4

-2 × 1/2 = -1

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3 years ago
mrs.price purchases 24 tickets for the students in her class. evaluate the expression t=24 please help I'm stuck and I don't kno
GuDViN [60]

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Step-by-step explanation:

6 0
2 years ago
Consider a system consisting of three independent components. Suppose the lifetimes of these components follow an Exponential di
Klio2033 [76]

Answer:

0.3723

Step-by-step explanation:

We are given a system  consisting of three independent components.

Let the three components be A , B and C

The lifetimes of these components follow an Exponential distribution with mean 300 hours, 410 hours, and 600 hours, respectively

a) Suppose that the system works only if all three components are functional (e.g., series connection). Find the probability that the system still works after 550 hours.

Exponential Distribution : 1-e^{-\lambda x}

P(A)=P(x>550) =1-e^{-\lambda \times 550}

\lambda=\frac{1}{\mu}

P(A)=P(x>550) =1-e^{-\frac{1}{300} \times 550}

P(A)=P(x>550) =0.8401

P(B)=P(x>550) =1-e^{-\frac{1}{410} \times 550}

P(B)=P(x>550) =0.7385

P(C)=P(x>550) =1-e^{-\frac{1}{600} \times 550}

P(C)=P(x>550) =0.6001

Since P(A) , P(B) , P(C) are independents

So, the probability that all three components still work after 550 hours = P(A)*P(B)*P(C)=0.8401 \times 0.7385 \times 0.6001 = 0.3723

Hence the probability that all three components still work after 550 hours is 0.3723

3 0
3 years ago
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