Answer:
The minimum score required for an interview is 77.252
Step-by-step explanation:
We solve this using z score formula
z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.
Top 15% of the candidates is a ranking that is equivalent to = 100 - 15% = 85th percentile.
The z score of 85th percentile = 1.036
Mean = 70
Standard Deviation = 7
Minimum score = raw score = ???
Hence:
1.036 = x - 70/7
Cross Multiply
1.036 × 7 = x - 70
7.252 = x - 70
x = 70 + 7.252
x = 77.252
The minimum score required for an interview is 77.252
It would be 10
You substitute “x”for “3” so the equation would be 2(3) + 4. Then you multiply 2 and 3, which is 6. Finally add the 4 to get 10.
Answer:
<h2>LCD = 9</h2>
Equivalent Fractions with the LCD
1/3 = 3/9
5/9 = 5/9
Solution:
Rewriting input as fractions if necessary:
1/3, 5/9
For the denominators (3, 9) the least common multiple (LCM) is 9.
LCM(3, 9)
Therefore, the least common denominator (LCD) is 9.
Calculations to rewrite the original inputs as equivalent fractions with the LCD:
1/3 = 1/3 × 3/3 = 3/9
5/9 = 5/9 × 1/1 = 5/9
The answr is 2 okay that’s the answer
