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LuckyWell [14K]
3 years ago
5

Are integers always whole numbers?

Mathematics
2 answers:
serg [7]3 years ago
7 0

Answer:

if I'm thinkng straight integers do always have to be whole numbers but they also can be negative

svetlana [45]3 years ago
6 0

Answer:

Not all integers are whole numbers or natural numbers. For example, -5 is an integer but not a whole number or a natural number.

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A lunette is a semicircular window that is sometimes placed above a doorway or above a rectangular window. A certain lunette has
soldier1979 [14.2K]

A lunette is a semi-circle, which means that it is one half of a circle. To find its area, we can find the area of the whole circle and divide it by two.

Area of a circle: A = pi x r^2

r = 40 / 2 = 20

A = pi x 20^2

A = 400pi / 2 = 200pi

200pi = 628.32

The area of the lunette is approximately 628 in^2.

Hope this helps!! :)

8 0
4 years ago
The line x = 6 is:<br> A. Cannot be determined<br> B. Horizontal<br> C. Neither<br> D. Vertical
jeka94

Answer:

Vertical

Step-by-step explanation:

Vertical line crossing the x-axis at 6. It does not cross the y-axis.

6 0
4 years ago
What relations are functions
Inessa05 [86]

The requirement is that every element in the domain must be connected to one - and one only - element in the codomain.


A classic visualization consists of two sets, filled with dots. Each dot in the domain must be the start of an arrow, pointing to a dot in the codomain.


So, the two things can't can't happen is that you don't have any arrow starting from a point in the domain, i.e. the function is not defined for that element, or that multiple arrows start from the same points.


But as long as an arrow start from each element in the domain, you have a function. It may happen that two different arrow point to the same element in the codomain - that's ok, the relation is still a function, but it's not injective; or it can happen that some points in the codomain aren't pointed by any arrow - you still have a function, except it's not surjective.

6 0
3 years ago
Area of a semicircle is 308cm. Find the perimeter
fgiga [73]

Answer:

72 cm

Step-by-step explanation:

Find the radius using the given information

308=1/2(πr^2)

r^2=616/π

r=14

The perimeter is πr + 2r so plug in 14

π(14) + 2(14)

43.96+28=71.96

3 0
3 years ago
If y = 9 inches, z = 14 inches, h = 5 inches, and w = 4 inches, what is the area of the object?
vekshin1

Answer:

126

Step-by-step explanation:

7 0
1 year ago
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