The answer is A
Explanation: 11x11=121
121x1/5=121/5
If you need area of the trapezoids:
Area of parallelogram = 10×7 = 70 sq. units
Area of each trapezoid = 1/2 × area of parallelogram = 1/2 × 70 = 35 sq. units
Answer:
Let the Dulcina's collection be 'x'
Let the Tremaine collection be 'x-39'
x + x - 39 =129
2x = 129 +39
2x = 168
x = 168/2
x = 84
Dulcina's collection = x = 84
Tremaine's collection = x - 39 = 84 - 39 = 45
The volume of the cylinder is equal to the sum of all spheres
the volume of 1 sphere is V1=4/3×pi×(1/2 x)³
simplified V1=1/6×pi×x²
we conclude that the volume of the cylinder is V2=270V1
V2=45×pi×x³
also the V2 can be calculated from the cylinder
V2= base(circle)×height
V2=(3x)²×pi×h=9x²×h
so we have
9x²×pi×h=45×pi×x³
simplified h=5x
Answer:
B=-1
Step-by-step explanation:
Standard form is Ax+By=C.
In this case, Ax is x, By is 1/5y, and C is +2.
To isolate the 2 (the C), subtract x from both sides of the equation:
x+2=1/5y
-x -x
2=-x+1/5y.
Now, the value of B, the x value, is -1.
