To solve this problem you must apply the proccedure shown below:
1. The problem asks for the area of a cross section that is parallel <span>to face ABCD. As is parallel to that face, you have can calculate its area as following:
A=12 cm x 6 cm
2. Therefore, the result is:
A=72 cm</span>²
The answer is: T<span>he area of a cross section that is parallel to face ABCD is 72 cm</span>².
Answer:
Step-by-step explanation:
its B
just chuck it in wolfram alpha
72+72+144 and 144 minus 360 equals 216 so half of 216 is 10. so the top and bottom are 108 degrees.
Answer:
KON
Step-by-step explanation:
