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Archy [21]
3 years ago
6

Type the base. 1/(7 ^ 2)​

Mathematics
1 answer:
Butoxors [25]3 years ago
7 0

Answer:

,,,,,,,,,,,,,, mmmmm mm m m m

Step-by-step explanation:

 m mm m m m mm m

You might be interested in
Use the distance formula to find the distance between each pair of points. Round your answers to the nearest hundredths place W
Elodia [21]

Answer:

The answer is

<h2>5.83 units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  }  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

W (-3,-5) and T (2,-2)

The distance between them is

|WT|  =  \sqrt{ ({ - 3 - 2})^{2} + ( { - 5 + 2})^{2}  }  \\  =  \sqrt{ ({ - 5})^{2} + ( { - 3})^{2}  }  \:  \:  \:   \\  =  \sqrt{25 + 9}  \\  =  \sqrt{34}  \:  \:  \:  \:  \:  \:  \:  \:  \\  = 5.830951

We have the final answer as

<h3>5.83 units to the nearest hundredth</h3>

Hope this helps you

3 0
3 years ago
Read 2 more answers
jeff used 3 cups of sugar to make 60 cookies. how many cups of sugar does he need to make 100 cookies?
Natasha2012 [34]

Answer:

5 cups of sugar

Step-by-step explanation:

To make 60 cookies you need 3 cups of sugar.

If you divide 60 / 3 you get 20.

That means: 1 cup = 20 cookies

Therefore to make 100 cookies you need 5 cups of sugar!

7 0
3 years ago
Read 2 more answers
I think its D, am I correct? plzz answer quickly!
serg [7]
The answer is the second option:
6/h = 10/40
4 0
3 years ago
Whats 8.00 divided by 1.50
Anna11 [10]
5.3repeated

Hope this helps
5 0
4 years ago
Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = Product of the two numbers.
Naddik [55]
Sol. (1) Prime factors of 26 = 2 x 13
Prime factors of 91 = 7 x 13
Hence, HCF = Common factors between 26 and 91 =13 and LCM=13x2x7=182

Now product of numbers 26 and 91
= 26 x 91 = 2366 and Product of HCF and LCM = 13 x 182 = 2366

So, it verify that product of two numbers = Product of HCF and LCM.

(2) Prime factors of 510 = 2 x 3 x 5 x 17
Prime factors of 92 = 2 x 2 x 23
Hence,HCF=2 and LCM=2×2×3 × 5×17×23 =23460

Now product of Numbers 510 and 92 = 46920 and product of HCF and LCM = 2 x 23460= 46920

Hence, verified that product of two numbers 18 equal to product of their HCF and LCM.

(3) Prime factors of336 = 2 x 2 x 2 x 2 x 3 x 7

Prime factors of 54 = 2 x 3 x 3 x 3
Hence, HCF (Product of common factors of 336 and 54)
=2 x 3=6

And LCM (Product of all common factors with remaining factors)
=(2 x 3)x 2 x 2 x 2 x 3 x 3 x 7=3024

Now, product of numbers 336 and 54 = 336 x 54 = 18144
and product of HCF and LCM = 6 x 3024 = 18144
Hence, product of two numbers: Product of HCF and LCM.
5 0
3 years ago
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