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cluponka [151]
3 years ago
5

What is 169.56 rounded to the nearest hundredths?

Mathematics
1 answer:
dedylja [7]3 years ago
3 0
It is already rounded to the nearest hundreth. .5 is a tenth, .06 is a hundreth.
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Identify the value of x and the length of each secant segment.
uranmaximum [27]

Answer:

x=7; NL=12; NP+20

Step-by-step explanation:

8 0
3 years ago
Would the sum of -13 and 20 be positive or negative? Explain your reasoning. Use complete sentences.
Debora [2.8K]

Answer:

Positive

Step-by-step explanation:

-13 plus positive 20 equals positive 7

6 0
3 years ago
George is considering two different investment options. The first option offers 7.4% per year simple interest on the
jok3333 [9.3K]

Answer:

Part A: The value of the simple interest investment at the end of three years is $12,220

Part B: The value of the compounded quarterly interest investment at the end of three years is $12,134.08

Part C: The simple interest investment is better over the first three years

Part D: I advise George to invest his money in the compounded interest investment if he will keep the money for a long time

Step-by-step explanation:

Part A:

A = P + P r t, where

  • A represents the value of the investment
  • P represents the original amount
  • r represents the  rate in decimal
  • t represents the time in years

∵ George deposits $10,000

∴ P = 10,000

∵ First option offers 7.4% per year simple interest

∴ r = 7.4% = 7.4 ÷ 100 = 0.074

∵ He may not withdraw any of  the money for three years after

   the initial deposit

∴ t = 3

- Substitute all of these values in the formula above

∴ A = 10,000 + 10,000(0.074)(3)

∴ A = 10,000 + 2,220

∴ A = 12,220

The value of the simple interest investment at the end of three years is $12,220

Part B:

A=P(1+\frac{r}{n})^{nt}, where

  • A represents the value of the investment
  • P represents the original amount
  • r represents the  rate in decimal
  • n is a number of periods of a year
  • t represents the time in years

∵ George deposits $10,000

∴ P = 10,000

∵ The second option offers a 6.5% interest rate compounded quarterly

∴ r = 6.5% = 6.5 ÷ 100 = 0.065

∴ n = 4 ⇒ quarterly

∵ He may not withdraw any of  the money for three years after

   the initial deposit

∴ t = 3

- Substitute all of these values in the formula above

∴ A=10,000(1+\frac{0.065}{4})^{(4)(3)}

∴ A=10,000(1.01625)^{12}

∴ A = 12,134.08

The value of the compounded quarterly interest investment at the end of three years is $12,134.08

Part C:

∵ 12,220 > 12,134.08

∴ The simplest interest investment is better than the compounded

    interest investment at the end of three years

The simple interest investment is better over the first three years

Part D:

I advise George to invest his money in the compounded interest investment if he will keep the money for a long time

Look to the attached graph below

  • The red line represents the simple interest investment
  • The blue curve represents the compounded interest investment
  • (Each 1 unit in the vertical axis represents $1000)
  • After 0 years and before 4.179 years the red line is over the blue curve, that means the simple interest is better because it gives more money than the compounded interest
  • After that the blue curve is over the red line that means the compounded quarterly is better because it gives more money than the simple interest

4 0
3 years ago
in 1996,Donovan Bailey of Canada ran the 100 meter dash in 9.84 seconds.How fastis that to the nearst second?to the nearst tenth
Fofino [41]
I think that you round to 9.80 seconds. Pardon me, I didn't understand the problem well
7 0
3 years ago
What is 9/10 + 7/15
Yakvenalex [24]

\huge\text{Hey there!}

\mathsf{\dfrac{9}{10}+\dfrac{7}{15}}

\large\textsf{FIRST: FIND the LCD (Lowest Common Denominator) then solve}\\\large\textsf{from there!}

\large\textsf{If you have calculated it correctly, you should have came up with \underline{\bf 30}}\\\large\textsf{as your LCD (Lowest Common Denominator).}

\mathsf{= \dfrac{9\times3}{10\times3}+ \dfrac{7\times2}{15\times2}}

\mathsf{9\times3=\bf 27}\\\mathsf{10\times3=\bf 30}\\\\\mathsf{7\times2=\bf 14}\\\mathsf{15\times2=\bf 30}

\mathsf{= \dfrac{27}{30}+\dfrac{14}{30}}

\mathsf{= \dfrac{27+14}{30}}

\mathsf{27+ 14=\bf 41}\\\\\mathsf{30+0=\bf 30}

\mathsf{= \dfrac{41}{30}}\large\textsf{ which you could convert to }\mathsf{1 \dfrac{11}{30}}

\boxed{\boxed{\large\textsf{ANSWER: }\bf \dfrac{41}{30} \large\textsf{ or }\mathsf{\bf 1 \dfrac{11}{30}\large\textsf{ because they both equal the same thing}}}}}\huge\checkmark

\large\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

6 0
2 years ago
Read 2 more answers
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