Answer:

Step-by-step explanation:
3x + y = 8 ----------------------(1)
2x + 4y = 12 -------------------(2)
Multiply Eq. (1) by 4
4(3x+y) = 8*4
12x + 4y = 32 -----------------(3)
Subtract Eq. (3) from (2)
2x + 4y - (12x + 4y) = 12 - 32
2x + 4y - 12x - 4y = -20
2x - 12x = -20
-10x = -20
Divide both sides by -10
x = 2
<u>Put x = 2 in Eq. (1)</u>
3(2) + y = 8
6 + y = 8
Subtract 6 to both sides
y = 8 - 6
y = 2
Solution Set = {(x,y)} = {(2,2)}
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3 /><h3>~AH1807</h3><h3>Peace!</h3>