Answer:
<em>2/3 of the jar was filled with flour</em>
Step-by-step explanation:
The question is incomplete. Here is the complete question.
<em>A jar can hold 3/4 of a pound of flour. Austin empties 1/2 of a pound of flour into the jar. What fraction of the jar is filled? Enter your answer in numerical form.</em>
<em />
Given
<em>Amount a jar can hold a = 3/4 of a pound of flour</em>
<em />
<em>If Austin empties 1/2 of a pound of flour into the jar, then the amount emptied into the jar b = 1/2 pounds</em>
<em />
<em>Fraction of jar filled will be expressed as b/a as shown;</em>
<em>b/a = (1/2)/(3/4)</em>
<em>b/a = 1/2 ÷ 3/4</em>
<em>b/a = 1/2 * 4/3</em>
<em>b/a = 4/6</em>
<em>Simplify to the lowest term</em>
<em>a/b = 2*2/2*3</em>
<em>a/b = 2/3</em>
<em />
<em>Hence 2/3 of the jar was filled with flour</em>
If you would like to know the volume of the cube, you can calculate this using the following steps:
volume = length * width * height
volume = 1 * 1 * 1
volume = 1
The volume of a cube is 1.
Answer:
No. It is not an Exponential Equation.
Step-by-step explanation:
Given
By the Definition of Exponential Equation which states.
"The equation is said to be an exponential equation when it has a variable occurred in the exponent and which have the same base."
For Example:
All given below are said to be exponential equations.
which can be rewritten as
Now in the given equation 
it doesn't have same base neither any means the base can be made same,hence the given equation is not an exponential equation
If you get 0 as the last value in the bottom row, then the binomial is a factor of the dividend.
Let's say the binomial is of the form (x-k) and it multiplies with some other polynomial q(x) to get p(x), so,
p(x) = (x-k)*q(x)
If you plug in x = k, then,
p(k) = (k-k)*q(k)
p(k) = 0
The input x = k leads to the output y = 0. Therefore, if (x-k) is a factor of p(x), then x = k is a root of p(x).
It turns out that the last value in the bottom row of a synthetic division table is the remainder after long division. By the remainder theorem, p(k) = r where r is the remainder after dividing p(x) by (x-k). If r = 0, then (x-k) is a factor, p(k) = 0, and x = k is a root.
