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Oduvanchick [21]

3 years ago

7

Construct an equilateral triangle with the line segment below. Make sure to mark 1) the angles that are equal 2) the sides that

are equal.

1 answer:

lilavasa [31]3 years ago

4 0

Answer:

There is no line segment...

Explanation of why I cannot solve:

No line segment

Answer:

$NoSolutions$

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Suppose a jar contains 5 red marbles and 25 blue marbles. If you reach in the jar and pull out one marble at random, do not repl

dsp73

Answer:

Probability that event will have both red marbles will be 2.3% or 0.023.

Step-by-step explanation:

Given:

Total red marbles=5

Total blue marbles=25

Total number of marbles =30

To Find:

The probability that both are red without replacement of marbles.

Solution:

Now

Total sample space is 30 and total red marbles are 5

For a event that getting red marble probability is ,

=Total red marbles /total marbles.

=5/30

=1/6

So probability if getting red marble is 1/6

<em>Now for second chance there will be 4 red marbles remaining and 29 total marbles so,</em>

In second chance probability if getting red marble will be

=total red marbles present/total marbles remaining

=4/29

Now ,

The required probability will be getting both at a time

i.e probability getting red AND red marble so here AND operator which means multiple both the probability.

Probability both will have red =1/6*4/29

=4/(29*6)=2/(29*3)

=0.022988

=0.023

=2.3 %

8 0

2 years ago

HELP!! <br> 9. What is the area of triangle AOB?

Akimi4 [234]

Angles ∠ACD and ∠CAB are congruent because they are alternate angles. Then the area of the triangle AOB will be 22.53 square cm.

<h3>What is the area of the right-angle triangle?</h3>

The area of the right-angle triangle is given as

A = 1/2 x B x H

Where B is the base and H is the height of the right triangle.

We know that angles ∠ACD and ∠CAB are congruent because they are alternate angles.

α₁ = 40°

AO = OC = 7.8 cm

Then the area of the triangle will be

Area = 1/2 x 7.8 x 7.8 x tan40°

Area = 22.53 square cm

More about the area of the right-angle triangle link is given below.

brainly.com/question/16653962

#SPJ1

5 0

1 year ago

In the school library, 28% of the books are non-fiction. If there are 1,224 fiction books in the library, what is the total numb

N76 [4]

Answer:

<em>There are 1700 books in the library.</em>

Step-by-step explanation:

<em>If 28% of the books is non-fiction, that means the remaining 72% of books are fiction.</em>

If 72% of the books are fiction, 1224/72 will give us 1%, which is 17.

If 1% is 17 books, then 17*100=100% of books.

There are 1700 books in the library.

8 0

2 years ago

HELPPPP PLEASE HELP ME WITH BASIC MATH I REALLY APPRECIATE IT ((WILL MARK AS BRAINLIEST))

Yakvenalex [24]

Answer:

3) 522

4) 468

Step-by-step explanation:

hello!

3) in the question, it says the cross section is a square, and the area of PQRS is 81.

for the square, we know that the length and height have to be the same, so if the area is 81, then we know the sides are both 9 because 9*9 is 81 and they're the same numbers multiplied. (same height and length)

with the information that all 4 sides of the square is 9 and the other side is labeled 10, we can figure out the rest.

both squares : 81+81=162

both 10 by 9 sides: 90+90=180

both 10 by 9 sides (top and bottom): 90+90=180

total surface area=162+180+180=522

4) for this problem, we can see that the triangle is a right triangle.

to solve the area of the triangle, we can do (9*12)/2=108/2=54.

there are two sides with triangles, so we double 54 (54*2=108)

9 by 10 side: 90

10 by 12 side: 120

now for the last slide, theres no information on the length. the formula for the diagonal is

a^2+b^2=c^2

which is

9^2+12^2=81+144=255=15^2

with this, the area of the rectangular side gives us 10*15 which is 150.

adding it together, we get

108+90+120+150=468.

hope this helps!

7 0

2 years ago

Can someone help me ? And show me the steps

kow [346]

If the line is parallel, it has the same slope. So now just find the y intercept and put it into slope-intercept form

3 0

3 years ago