We know that the points at which the parabola intersects the x axis are
(-5,0) and (1,0)
So the extent between these two points would be the base of the triangle
lets find the length of the base using the distance formula
![\sqrt{[(-5-1)^{2}+(0-0)^{2} ]}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%5B%28-5-1%29%5E%7B2%7D%2B%280-0%29%5E%7B2%7D%20%5D%7D%20%20)
the base b=6
We will get the height of the triangle when we put x=0 in the equation
y=a(0+5)(0-1)
y=-5a
so height = -5a (we take +5a since it is the height)
We know that the area of the triangle =
× 6 × (5a) = 12
15a=12
a= 
Answer: x=34
Step-by-step explanation:
1. You subtract 2x from 5x on the other side to get rid of the 2x leaving you with 3x.
2. Then you add 5 to 97 to get rid of the -5, giving you 102 on the opposite side.
3. divide 102 by 3x giving you 34.
5x-5=2x+97
-2x -2x
3x-5=97 <u><em>X=102</em></u>
+5 +5
3x=102
x/3 102/3
Answer:
stuff i be steelin ur points
Step-by-step explanation:
Answer:
1.6 please correct me if im wrong by commenting
Step-by-step explanation:
