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NNADVOKAT [17]
2 years ago
10

Express q(x)=12x^5+40x^4-32x^3 in the form described in the Linear Factorization Theorem. List each zero and its multiplicity.

Mathematics
1 answer:
miskamm [114]2 years ago
3 0

Polynomial is an expression that consists of indeterminates(variable) and coefficients. The multiplicity of 0 is 3, 2/3 is 1 and -4 is 1.

<h3>What are polynomials?</h3>

Polynomial is an expression that consists of indeterminates(variable) and coefficients, it involves mathematical operations such as addition, subtraction, multiplication, etc, and non-negative integer exponentials.

Given polynomial equation q(x)=12x⁵+40x⁴-32x³, therefore, the factorised form of the equation will be,

q(x)=12x^5+40x^4-32x^3\\\\q(x)=4x^3(3x^2+10x-8)\\\\q(x)=(4x^3-0)(3x^2+12x-2x-8)\\\\q(x)=(4x^3-0)[3x(x+4)-2(x+4)]\\\\q(x) = (4x^3-0)(3x-2)(x+4)

Therefore, the multiplicity of 0 is 3, 2/3 is 1 and -4 is 1.

Learn more about Polynomial:

brainly.com/question/17822016

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alisha [4.7K]

Answer:

  • - 179 ft

Step-by-step explanation:

Start elevation is 0 ft

Change of position after 50 seconds

  • 50*4.5 = 225 ft

Elevation now

  • 0 - 225 = - 225 ft

Change of position after 92 seconds

  • 92*0.5 = 46 ft

Final elevation

  • - 225 + 46 = - 179 ft
5 0
2 years ago
50 POINTS
larisa86 [58]

Answer:

see below

Step-by-step explanation:

f(x) = 5x^3 +1, g(x) = – 2x^2, and h(x) = - 4x^2 – 2x +5

f(-8) = 5(-8)^3 +1 = 5 *(-512) +1 =-2560+1 =-2559

g( -6) = -2 ( -6) ^2 = -2 ( 36) = -72

h(9) = -4( 9)^2 -2(9) +5 = -4 ( 81) -18+5 = -324-18+5=-337

3 0
3 years ago
Read 2 more answers
A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co
Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let \mu = <u><em>mean weight of coffee in its containers.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq 32 ounces     {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, H_A : \mu < 32 ounces      {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                             T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean weight = 31.8 ounces

             s = sample standard deviation = 0.48 ounces

             n = sample of containers = 15

So, <u><em>the test statistics</em></u>  =  \frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }  ~ t_1_4  

                                      =  -1.614

The value of t test statistics is -1.614.

<u>Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.</u>

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

8 0
3 years ago
Mary is trying to decide what potato chips she wants for a snack. In her variety bag there are 4 salt and vinegar, 2 BBQ, 12 Dor
zzz [600]
If she reaches to the bottom of the nag she will most likely to find the Doritos
4 0
3 years ago
Let z be the product of any 5 consecutive three digit odd natural numbers. When you multiply
Charra [1.4K]

Answer:

  5

Step-by-step explanation:

If x is the middle number of the 5 consecutive odd numbers, their product is ...

  x(x -2)(x +2)(x -4)(x +4) = x(x² -4)(x² -16)  = x⁵ -20x³ +64x

The first 3-digit prime is 101, so the product of that with this is ...

  101(x⁵ -20x³ +64x) = 101x⁵ -2020x³ +6464x

Since we're only interested in the units digit, we can find the mod 10 value of this to be ...

  (x⁵ +4x) mod 10

Possible units digits of x are 1, 3, 5, 7, 9, so possible units digits of this product are ...

  x(x⁴ +4) = 1(1⁴ +4) = 5

  3(3⁴ +4) = 3(1 +4) = 5 . . . . mod 10

  5(5⁴ +4) = 5(5 +4) = 5 . . . . mod 10

  7(7⁴ +4) = 7(1 +4) = 5 . . . . mod 10

  9(9⁴ +4) = 9(1 +4) = 5 . . . . mod 10

In every case, the units digit of 101z will be 5.

4 0
2 years ago
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