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Mariulka [41]
3 years ago
7

Marie mixes 20 liters of 12% acid solution with a 36% acid solution to make a 20% acid solution. How many liters of 36% solution

did she use?
Mathematics
1 answer:
kykrilka [37]3 years ago
6 0
Use c1v1+c2v2=c3v3
where c=concentration, v=volume.

C1=0.12
V1=20 L
C2=0.36
V2=X
C3=0.20
V3=20+X L

Substitute in equation
0.12(20) + 0.36X = 0.20(20+X)
Expand 
2.4 + 0.36X = 4 + 0.2X
Simplify
(0.36-0.2)X = 4-2.4
0.16X = 1.6
X=1.6/0.16 = 10 L

check:
0.12(20)+0.36(10)=2.4+3.6=6.0
(20+10)*0.20 = 6.0  so solution is good.

Answer: Volume of 36% solution is 10L
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Greetings!

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Example:
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1/9x^{2}

Hope this helps.
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3 years ago
Find the total surface area and volume, then multiply by 0.0004
Maksim231197 [3]

The Total surface area of the rectangular prism = 168 in.²

The Volume of the rectangular prism = 108 in.³

<h3>What is the Total Surface Area of a Rectangular Prism?</h3>

The total surface area of a rectangular prism is given as: SA = 2(wl + hl + hw), where:

w = width of the rectangular prism

h = height of the rectangular prism

l = length of the rectangular prism

<h3>What is the Volume of a Rectangular Prism?</h3>

The volume of a rectangular prism = l × w × h

Find the Total surface area of the rectangular prism:

Length (l) = 9 in.

Width (w) = 2 in.

Height (h) = 6 in.

Total surface area of the rectangular prism = 2(wl+hl+hw) = 2·(2·9+6·9+6·2) = 168 in.²

Find the volume of the rectangular prism:

Length (l) = 9 in.

Width (w) = 2 in.

Height (h) = 6 in.

Volume of the rectangular prism = l × w × h = 9 × 2 × 6

Volume of the rectangular prism = 108 in.³

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7 0
2 years ago
Suppose the graph of a cubic polynomial function has the same zeroes and passes through the coordinate (0, -5). Write the equati
amid [387]
In this we know all three zeros and one point from which the graph pass.
So we will let specific cubic polynomial function of the form
f(x) = a(x - x_1)(x-x_2)(x-x_3)

As we know zeros are that point where we will get value of function equal to zero. So it is basically in form (x_n , 0)

SO in given question zeros are (2 , 0) , (3, 0) and (5,0)
So we can say x_1 = 2 , x_2 = 3 , x_3 = 5

So required equation is
f(x) = a (x-2)(x-3)(x-5)
              = a[(x^2 - 2x - 3x + 6)(x-5)]
              = a[(x^2 - 5x+6)(x-5)]
              = a(x^3 - 5x^2 + 6x- 5x^2 + 25x - 30)
              = a(x^3 - 10x^2+31x-30)
Now we have one point (0 , -5) from which graph passes.
So we say at x = 0 , f(x) = -5
-5= a (0-0+0 - 30)
-5 = -30a
a =  \frac{-5}{-30} =  \frac{1}{6}
So required equation of cubic polynomial is
f(x) =  \frac{1}{6}(x^3 -10x^2+31x-30)

For finding y - intercept we simply plugin x = 0 in given equation.
As we know at x = 0 , value of function is -5.
So y - intercept is -5.
4 0
4 years ago
Read 2 more answers
Can someone please help me ;-; this is due today
IRISSAK [1]

Answer:

The correct answer: F (Scalene) and A (Acute)

Step-by-step explanation:

F. (Scalene):  By definition, a scalene triangle is a triangle that has no equal sides, and no equal angles. This definition matches your given triangle, since it has no equal sides and angles.

A. (Acute): By definition, an acute triangle is a triangle in which all the internal angles are less than 90 degrees. This definition matches your given triangle, since all of the internal angles are less than 90 degrees.

The given triangle is not obtuse, equilateral, right, and isoceles.

It is <u>not</u> an <em>obtuse </em>triangle because none of the angles are greater than 90 degrees.

It is <u>not</u> an <em>equilateral</em> triangle because its sides are not equal.

It is <u>not</u> a <em>right</em> triangle because none of its internal angles measure 90 degrees.

And it is <u>not</u> an <em>isoceles</em> triangle because by definition, an isoceles triangle must have two equal sides. Your given triangle has no equal sides.

6 0
3 years ago
Use a truth table to show that P Qand (~PV Q) A (~QV P) are equivalen
kati45 [8]

Answer:  The given logical equivalence is proved below.

Step-by-step explanation:  We are given to use truth tables to show the following logical equivalence :

P ⇔ Q ≡ (∼P ∨ Q)∧(∼Q ∨ P)

We know that

two compound propositions are said to be logically equivalent if they have same corresponding truth values in the truth table.

The truth table is as follows :

P     Q      ∼P     ∼Q     P⇔ Q    ∼P ∨ Q     ∼Q ∨ P        (∼P ∨ Q)∧(∼Q ∨ P)

T     T         F        F             T            T                   T                       T

T     F         F        T             F             F                   T                       F

F     T         T        F             F            T                   F                       F

F     F         T        T             T            T                   T                       T

Since the corresponding truth vales for P ⇔ Q and (∼P ∨ Q)∧(∼Q ∨ P) are same, so the given propositions are logically equivalent.

Thus, P ⇔ Q ≡ (∼P ∨ Q)∧(∼Q ∨ P).

8 0
4 years ago
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