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3 years ago

Answer the given question and show workings.

Mathematics

2 answers:

Katyanochek1 [597]3 years ago

8 0

Answer:

Step-by-step explanation:

<h3>Given</h3>

sin θ = 3/5
cos α = 3/5
Both angles are acute

<h3>Solution</h3>

Since both sin θ and cos α have same value of 3/5 and both angles are in the I quadrant, the angles θ and α are complementary.

It means:

θ + α = 90°
sin (θ + α) = sin 90° = 1

Minchanka [31]3 years ago

6 0

Answer:

alpha=cos^-1(0.6)

alpha=53°

sin(37+53)

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marshall27 [118]

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3 years ago

Write a quadratic function in standard form having zeros of -9 and -12

tia_tia [17]

(x + 9)(x + 12) = 0
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3 years ago

Math help please, thank you!

CaHeK987 [17]

The answer to the first question of the attached document is option 1. We obtain the answer subtracting the term n from the series with the term n-1.For example:
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The answer to the second question is option 3:
y = | x + 7 |
We can confirm it by substituting values in the equation.
For example:
if we do y = 0 then x = -7
if we do x = 0 then y = 7.
As corresponds in the graph shown.
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3 years ago

The graph represents the normal distribution of recorded weights, in pounds, of cats at a veterinary clinic.

diamong [38]

Answer:

B) 8.9 lbs

C) 9.5 lbs

D) 9.8 lbs

E) 10.4 lbs

Step-by-step explanation:

From the graph, 9.5 is the mean of the sample and 0.5 is the standard deviation of the sample.

As we have to find the weights that lie within the 2 standard deviations of the mean i.e

$=9.5\pm 2(0.5)$

$=8.5,10.5$

Among the given weights only 8.9 lbs, 9.5 lbs, 9.8 lbs, 10.4 lbs will lie within 2 standard deviations of the mean.

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3 years ago

Read 2 more answers

Write the sum using summation notation, assuming the suggested pattern continues. 5 - 15 + 45 - 135 + ...

nalin [4]

Answer:

summation of five times negative three to the power of n from n equals zero to infinity

Step-by-step explanation:

Summation Notation

It represents the sum of a finite or infinite number of terms. Let's analyze the terms of the given succession:

5-15+45-135+...

If we take 5 as a common factor, we have

5(1-3+9-27+...)

The parentheses contain the alternate sum/subtraction of powers of 3. The odd terms are positive, the even terms are negative, thus the exponent must be n starting from 0 or n-1 starting from 1

The summation is then represented by

$\sum_{n=0}^{\infty}5(-3)^n$

This corresponds with the option:

summation of five times negative three to the power of n from n equals zero to infinity

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3 years ago