Answer:
B. Yes, by the AA Similarity Postulate
Step-by-step explanation:
This triangles are both similar based on the AA Similarity Postulate. We know that all angles are equal because...
m∠ABE = m∠CBD = 42° (because they are veridical/opposite angels)
m∠AEB = 180° - m∠ABE - m∠EAB = 180° - 42° - 53° = 85°
Then from here we know that
m∠BDC = 180° - 85° - m∠CBD
m∠BDC = 95° - 42°
m∠BDC = 53°
From here we see that they are similar because of the AA Similarity Postulate, since
m∠ABE = m∠CBD = 42°
m∠BDC = m∠EAB = 53°
m∠AEB = m∠BCD = 85°
Step-by-step explanation:
so we know X= Numbers of Large boxes and Y= Numbers of Small boxes
And we know the large boxes weigh <em>7</em><em>5</em><em><u> </u></em><em><u>pounds</u></em> and the small boxes weigh <em>4</em><em>0</em><em> </em><em><u>pounds</u></em>
So I would have to say the the same except you have to flip the inequality sign like this:
75x + 40y
200
And if that doesnt somehow work and the question is wording it wrong then
My guess for why its wrong us because its not in slope intercept form Although you still can solve for either varible ( x or y) using standard form also.
So to get from standard form to Slope intercept form (y=mx+b) these are the steps:
Ax+by=C
75x + 40y ≤ 200
Turn it into a linear equation.
75x+ 40y =200
In order to go from one form to another, all you have to do is change the order of the given numbers. First you want to move the Ax to the opposite side of the equation, by either adding or subtracting it. At this point your equation will be set up By = -Ax + C. Then you want to divide the B from the By and the rest of the equation. Therefore you will have y = - Ax/B + C/B. This is the same thing as the slope-intercept form, just a few of the letters are different.
40y=-75x+200 first subtract 75x
y=−1.875×+5 then dived every varible (everything) by 40. and you have your Linear eqaution.
And your second question would be <em><u>A</u></em><em><u>.</u></em><em><u> </u></em><em><u>>The number of boxes must be a whole number.</u></em><em><u> </u></em>
Because you cannot split boxes in half or in any quarter in a real life scenario.
Yes, the set of vectors
V = {(x, y, z) : x - 2y + 3z = 0}
is indeed a vector space.
Let u = (x, y, z) and v = (r, s, t) be any two vectors in V. Then
x - 2y + 3z = 0
and
r - 2s + 3t = 0
Their vector sum is
u + v = (x + r, y + s, z + t)
We need to show that u + v also belongs to V - in other words, V is closed under summation. This is a matter of showing that the coordinates of u + v satisfy the condition on all vectors of V:
(x + r) - 2 (y + s) + 3 (s + t) = (x - 2y + 3z) + (r - 2s + 3t) = 0 + 0 = 0
Then V is indeed closed under summation.
Scaling any vector v by a constant c gives
cv = (cx, cy, cz)
We also need to show that cv belongs to V - that V is closed under scalar multiplication. We have
cx - 2cy + 3cz = c (x - 2y + 3z) = 0c = 0
so V is need closed under scalar multiplication.
Y= 7.5 than r= 1647 if this didn’t help than your welcome
Answer:
Step-by-step explanation:
Given
Required
Evaluate
Let:
Add both equations
Subtract both equations
So:
R is defined by the following boundaries:
,
So, we can not set up Jacobian
This gives:
Calculate the determinant
Now the integral can be evaluated:
becomes:
So:
Remove constants
Integrate v
Integrate u
Expand
Open bracket
Expand