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svet-max [94.6K]
3 years ago
8

Mia is standing 210 yd from a radio tower.

Mathematics
2 answers:
Artyom0805 [142]3 years ago
4 0

height = tan(11) x 210

height = 40.81 yards

 rounded to nearest tenth = 40.8 yards

vichka [17]3 years ago
3 0

Solution:

The height of the radio tower is 40.8 yd.

Explanation:

Let us draw a diagram for the given situation. In the attached diagram AB is the radio tower and Mia is standing at point C.

The angle of elevation is 11°. Hence, angle C is 11°.

Let the height of the tower is h.

In triangle ABC, we have

\tan \theta = \frac{AB}{BC} \\\\\tan 11^{\circ}=\frac{h}{210} \\\\h=210\tan 11^{\circ}\\\\h=40.8

Therefore, the height of the radio tower is 40.8 yd.

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A washer and dryer cost a total of $954. The cost of the washer is two times the cost of the dryer. Find the cost of each item.
scoray [572]

Answer:

The dryer would cost 318 and the washer would cost 636

Step-by-step explanation:

954 divided by 3 = 318  318x2=636     318+638=954

8 0
3 years ago
Describe the location of the sum, relative to p, on a number line<br> P+(-2)
il63 [147K]

Answer:

The location of the sum is 2 units before P (left to P)

Step-by-step explanation:

* <em>Lets describe the number line</em>

- A number line is a horizontal straight line with numbers placed at

 an equal units

- A number line can be extended infinitely to the left and to the right

- A number line represents both positive and negative integers

- The numbers come on it from left to right

- The negative numbers come on the left of zero and the positive

  numbers come on the right of zero

- Ex: -5 , -4 , -3 , -2 , -1 , 0 , 1 , 2 , 3 , 4 , 5 part of the numbers on the

 number line

- To add numbers on the number line we start from first number of

  the addition and if this number is added by a positive number we

  go to right , if the number is added by a negative number

  we go to left

- Ex: 5 + 3 ⇒ go from 5 to the right 3 units, then your position is at 8

 2 + (-3) ⇒ go from 2 to the left 3 units then your position is at -1

* <em>Now lets solve the problem</em>

- The sum of P + (-2)

∵ Your location is P

∵ You will add P by (-2)

- Negative number means you go to the left

∴ Your position will be before P by two units

∴ The location of the sum is 2 units before P (left to P)

5 0
3 years ago
Please help I will mark you as Brainly
Montano1993 [528]

Answer:

4

Step-by-step explanation:

Let's dissect the fraction.

x=8 y=1

2y=2

8/2=4

Hope this helps ;-))

5 0
4 years ago
Read 2 more answers
There are eight different jobs in a printer queue. Each job has a distinct tag which is a string of three upper case letters. Th
Vikentia [17]

Answer:

a. 40320 ways

b. 10080 ways

c. 25200 ways

d. 10080 ways

e. 10080 ways

Step-by-step explanation:

There are 8 different jobs in a printer queue.

a. They can be arranged in the queue in 8! ways.

No. of ways to arrange the 8 jobs = 8!

                                                        = 8*7*6*5*4*3*2*1

No. of ways to arrange the 8 jobs = 40320 ways

b. USU comes immediately before CDP. This means that these two jobs must be one after the other. They can be arranged in 2! ways. Consider both of them as one unit. The remaining 6 together with both these jobs can be arranged in 7! ways. So,

No. of ways to arrange the 8 jobs if USU comes immediately before CDP

= 2! * 7!

= 2*1 * 7*6*5*4*3*2*1

= 10080 ways

c. First consider a gap of 1 space between the two jobs USU and CDP. One case can be that USU comes at the first place and CDP at the third place. The remaining 6 jobs can be arranged in 6! ways. Another case can be when USU comes at the second place and CDP at the fourth. This will go on until CDP is at the last place. So, we will have 5 such cases.

The no. of ways USU and CDP can be arranged with a gap of one space is:

6! * 6 = 4320

Then, with a gap of two spaces, USU can come at the first place and CDP at the fourth.  This will go on until CDP is at the last place and USU at the sixth. So there will be 5 cases. No. of ways the rest of the jobs can be arranged is 6! and the total no. of ways in which USU and CDP can be arranged with a space of two is: 5 * 6! = 3600

Then, with a gap of three spaces, USU will come at the first place and CDP at the fifth. We will have four such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 4 * 6!

Then, with a gap of four spaces, USU will come at the first place and CDP at the sixth. We will have three such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 3 * 6!

Then, with a gap of five spaces, USU will come at the first place and CDP at the seventh. We will have two such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 2 * 6!

Finally, with a gap of 6 spaces, USU at first place and CDP at the last, we can arrange the rest of the jobs in 6! ways.

So, total no. of different ways to arrange the jobs such that USU comes before CDP = 10080 + 6*6! + 5*6! + 4*6! + 3*6! + 2*6! + 1*6!

                    = 10080 + 4320 + 3600 + 2880 + 2160 + 1440 + 720

                    = 25200 ways

d. If QKJ comes last then, the remaining 7 jobs can be arranged in 7! ways. Similarly, if LPW comes last, the remaining 7 jobs can be arranged in 7! ways. so, total no. of different ways in which the eight jobs can be arranged is 7! + 7! = 10080 ways

e. If QKJ comes last then, the remaining 7 jobs can be arranged in 7! ways in the queue. Similarly, if QKJ comes second-to-last then also the jobs can be arranged in the queue in 7! ways. So, total no. of ways to arrange the jobs in the queue is 7! + 7! = 10080 ways

5 0
4 years ago
2.
Virty [35]

Answer:

1/9 is probably most likely the correct answer

3 0
3 years ago
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