Answer:
13
Step-by-step explanation:
<em>Divide 50 from 650.</em>
<em>650 / 50 </em>
<em>13</em>
<em>This proves she sold 13 handbags</em>
256. Since each side is congruent, the length equals 8. 8 times 8 equals 64. Divide it by 2 to find the area of the triangle. 64 divided by 2 equals 32. Since there are 8 congruent triangles, 32 x 8 equals 256.
Answer: for a the answer is 140° and for b x=25°
Step-by-step explanation:
for a, when you have 2 parallel lines cut by a transversal,the corresponding angles are congruent. and the angle140 is congruent to the corresponding angle as they are vertical angles are congruent.
for b, angle x is congruent to the angle that is supplementary to 155 therefore 180-155=25°
Answer:
The answer is C. 546.
If a population decreases by 11%, that means that 89% (100% - 11% = 89%) of cheetahs remains each number. 89% can be expressed as 0.89, so to calculate the change of the population, we must each year multiply the number of cheetahs by 0.89.
After 1 year: 1750 * 0.89 ≈ 1558
After 2 years: 1558 * 0.89 ≈ 1387
After 3 years: 1387 * 0.89 ≈ 1234
After 4 years: 1234 * 0.89 ≈ 1098
After 5 years: 1098 * 0.89 ≈ 977
After 6 years: 977 * 0.89 ≈ 870
After 7 years: 870 * 0.89 ≈ 774
After 8 years: 774 * 0.89 ≈ 689
After 9 years: 689 * 0.89 ≈ 613
After 10 years: 613 * 0.89 ≈ 546
Step-by-step explanation:
Answer: (751.05, 766.95)
Step-by-step explanation:
We know that the confidence interval for population mean is given by :-
,
where 
=population standard deviation.
= sample mean
n= sample size
z* = Two-tailed critical z-value.
Given : 
n= 42
We know that from z-table , the two-tailed critical value for 99% confidence interval : z* =2.576
Now, the 99% confidence interval around the true population mean viscosity :-
![759\pm (2.5760)\dfrac{20}{\sqrt{42}}\\\\=759\pm (2.5760)(3.086067)\\\\=759\pm7.9497=(759-7.9497,\ 759+7.9497)\]\\=(751.0503,\ 766.9497)\approx(751.05,\ 766.95)](https://tex.z-dn.net/?f=759%5Cpm%20%282.5760%29%5Cdfrac%7B20%7D%7B%5Csqrt%7B42%7D%7D%5C%5C%5C%5C%3D759%5Cpm%20%282.5760%29%283.086067%29%5C%5C%5C%5C%3D759%5Cpm7.9497%3D%28759-7.9497%2C%5C%20759%2B7.9497%29%5C%5D%5C%5C%3D%28751.0503%2C%5C%20766.9497%29%5Capprox%28751.05%2C%5C%20766.95%29)
∴ A 99% confidence interval around the true population mean viscosity : (751.05, 766.95)
