AC is a tangent so by definition, it touches the circle at exactly one point (point C) and forms a right angle at the tangency point. So angle ACO is 90 degrees
The remaining angle OAC must be 45 degrees because we need to have all three angles add to 180
45+45+90 = 90+90 = 180
Alternatively you can solve algebraically like so
(angle OAC) + (angle OCA) + (angle COA) = 180
(angle OAC) + (90 degrees) + (45 degrees) = 180
(angle OAC) + 90+45 = 180
(angle OAC) + 135 = 180
(angle OAC) + 135 - 135 = 180 - 135
angle OAC = 45 degrees
Side Note: Triangle OCA is an isosceles right triangle. It is of the template 45-45-90.
2x + 100 = 5x + 55
3x = 45
x = 15
2(15) + 100 = 130
180-130 = 50
so angle 2 is 50 degrees
Answer:
Graph the parabola using the direction, vertex, focus, and axis of symmetry.
Step-by-step explanation:
Answer:
<em>Answer</em><em>:</em><em>0</em><em>0</em>
If any individual factor on the left side of the equation is equal to 00, the entire expression will be equal to 00.
b=0b=0
3b−5=03b-5=0
Set the first factor equal to 00.
b=0b=0
Step-by-step explanation:
The result can be shown in multiple forms.
Exact Form:
b=0,53b=0,53
Decimal Form:
b=0,1.¯6b=0,1.6‾
Mixed Number Form:
b=0,123b=0,123
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