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natulia [17]
3 years ago
10

Which value must be added to the expression x^2– 3x to make it a perfect-square trinomial?

Mathematics
1 answer:
liraira [26]3 years ago
3 0

Answer:

\frac{9}{4}

Step-by-step explanation:

Given

x² - 3x

add ( half the coefficient of the x- term)²

x² + 2(- \frac{3}{2})x + (- \frac{3}{2})²

= (x - \frac{3}{2})² + \frac{9}{4}

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7 0
2 years ago
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Consider two independent tosses of a fair coin. Let A be the event that the first toss results in heads, let B be the event that
aliina [53]

Answer with Step-by-step explanation:

We are given that two independent tosses of a fair coin.

Sample space={HH,HT,TH,TT}

We have to find that A, B and C are pairwise independent.

According to question

A={HH,HT}

B={HH,TH}

C={TT,HH}

A\cap B={HH}

B\cap C={HH}

A\cap C={HH}

P(E)=\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}

Using the formula

Then, we get

Total number of cases=4

Number of favorable cases to event A=2

P(A)=\frac{2}{4}=\frac{1}{2}

Number of favorable cases to event B=2

Number of favorable cases to event C=2

P(B)=\frac{2}{4}=\frac{1}{2}

P(C)=\frac{2}{4}=\frac{1}{2}

If the two events A and B are independent then

P(A)\cdot P(B)=P(A\cap B)

P(A\cap)=\frac{1}{4}

P(B\cap C)=\frac{1}{4}

P(A\cap C)=\frac{1}{4}

P(A)\cdot P(B)=\frac{1}{2}\cdot \frac{1}{2}=\frac{1}{4}

P(B)\cdot P(C)=\frac{1}{4}

P(A)\cdot P(C)=\frac{1}{4}

P(A)\cdot P(B)=P(A\cap B)

Therefore, A and B are independent

P(B)\cdot P(C)=P(B\cap C)

Therefore, B and C are independent

P(A\cap C)=P(A)\cdot P(C)

Therefore, A and C are independent.

Hence, A, B and C are pairwise independent.

6 0
3 years ago
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pickupchik [31]

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3 0
2 years ago
What does x equal? 3(x-7)=138+3x
Arturiano [62]
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3x-21 = 138 + 3x      subtract 3x from both sides 
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This is a false statement because -21 does not equal to 138 so the answer is no solution.

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