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natulia [17]
3 years ago
10

Which value must be added to the expression x^2– 3x to make it a perfect-square trinomial?

Mathematics
1 answer:
liraira [26]3 years ago
3 0

Answer:

\frac{9}{4}

Step-by-step explanation:

Given

x² - 3x

add ( half the coefficient of the x- term)²

x² + 2(- \frac{3}{2})x + (- \frac{3}{2})²

= (x - \frac{3}{2})² + \frac{9}{4}

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The data given to the right includes data from ​candies, and of them are red. The company that makes the candy claims that ​% of
Dafna1 [17]

Using the z-distribution, the 95% confidence interval for the percentage of red candies is of (7.84%, 33.18%). Since 33% is part of the interval, there is not enough evidence to conclude that the claim is wrong.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

Researching this problem on the internet, 8 out of 39 candies are red, hence the sample size and the estimate are given by:

n = 39, \pi = \frac{8}{39} = 0.2051

Hence the bounds of the interval are:

  • \pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2051 - 1.96\sqrt{\frac{0.2051(0.7949)}{39}} = 0.0784
  • \pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2051 + 1.96\sqrt{\frac{0.2051(0.7949)}{39}} = 0.3318

As a percentage, the 95% confidence interval for the percentage of red candies is of (7.84%, 33.18%). Since 33% is part of the interval, there is not enough evidence to conclude that the claim is wrong.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

7 0
2 years ago
It cost Benjamin $1.35 to send 9 text messages how much would it cost to send 118 text messages
Allushta [10]

Answer:

it costs $17.7

Step-by-step explanation:

1.35/9 is 0.15

0.15 * 118 = 17.7

3 0
3 years ago
#10-1 : What is the probability of randomly choosing a diamond card from a regular deck of 52 cards? What is the probability of
Alchen [17]

\huge{\boxed{\frac{1}{4}}}\ \ \huge{\boxed{\frac{1}{4}}}

There are 13 of each suit in a deck of 52 cards.

This means the probability of drawing a diamond card is \frac{13}{52}. You can divide the numerator and denominator each by 13 to simplify. \frac{13}{52} \div \frac{13}{13} = \boxed{\frac{1}{4}}

Since there are the same number of clubs as there are diamonds, the probabilities are the same.

3 0
4 years ago
How many 3/4 are there in 5 1/4
Zinaida [17]

Answer:

7

Step-by-step explanation:

5 1/4= 5.25

3/4=.75

5.25/0.75=7

3 0
3 years ago
Read 2 more answers
Can someone answer this please??
ch4aika [34]
Volume of A = 1728

volume of B = 729  

<span> (1728 / 729) = (a / b)^3  (a = width of A, b = width of B)
  a / b = cube root (1728 / 729)  = 4/3   </span><span> b = 10 (given)
a / 10 = 4/3 </span><span>
  a = 40/3 = 13.33333</span>
 so width of A is 13.33m
6 0
3 years ago
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