1/2x-2/5=3/5 (BTW I got 2/5 by reducing 4/10)
1/2x=7/5 (BTW I got 7/5 by moving 2/5 to the other side)
Then do 7/5 times 2 and you get 14/5
14/5
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Explanation:
This question's it's about the order of operations. P-parenthesis, E-exponents, M-multiply, D-divide, A-add, and S-subtract. It can also go left to right.
Do exponents first.
Then, multiply left to right.
And add/subtract left to right.
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Answer:
log (16)=2 in base 3x-5
==>16=2^(3x-5)
==>2^4=2^(3x-5)
==>4=3x-5
==>3x=9
==>x=3
Step-by-step explanation:
Note: I'm afraid I can't put the work for the answers, for lack of time =/
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1. 0 or -3
2. 0 or 4
3. -2 or 3
4. 0 or 1/2
5. -2 or 3
6. 0 or 5
7. 0 or 7
8. 0 or -2
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9. Substitute 0 for h in "h = -16x^2 + 16x" then solve for x
0 = -16x^2 + 16x
<span>Subtract -16x^2+16x from both sides.
</span><span>0−<span>(<span><span>−<span>16x2</span></span>+16x</span>)</span></span>=<span><span><span>−<span>16<span>x2</span></span></span>+<span>16x</span></span>−<span>(<span><span>−<span>16x2</span></span>+16x</span>)
</span></span><span><span>16<span>x2</span></span>−<span>16x</span></span>=<span>0
</span>
Factor the left side of the equation
<span><span>16x</span><span>(<span>x−1</span>)</span></span>=<span>0
</span>
Set factors to equal 0
<span><span>16x</span>=<span><span><span>0<span> or </span></span>x</span>−1</span></span>=<span>0
</span>x = 0 or x = 1
