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LekaFEV [45]
4 years ago
6

THIS QUESTION IS EASY, I JUST NEED EXPLANATION.

Mathematics
2 answers:
chubhunter [2.5K]4 years ago
6 0

It would help to have the question. But I'll guess


\sqrt[4]{x^{\frac 3 5}}{\sqrt{x^2}} = ((x^{\frac 3 5})^{\frac 1 4}) }{ x} = x^{\frac 3{20}} x  = x \sqrt[20]{x^3}


2nd choice.


I forgot the explanation because I was so glad to have puzzled out the question.

The fourth root is the same as the 1/4 th power.   

If we know x is positive \sqrt{x^2}=|x|=x

\sqrt[4]{x^{\frac 3 5}}{\sqrt{x^2}}

= ((x^{\frac 3 5})^{\frac 1 4}) }{ x}

We multiply the powers: (a^b)^c=a^{bc}

= x^{\frac 3{20}} x

The one-twentieth power is the twentieth root.  We bring the additional factor of x to the front.

= x \sqrt[20]{x^3}

elena55 [62]4 years ago
3 0

Answer:the answer is A. ^20 sqrt x^7

Step-by-step explanation:

Just took the test

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