The answer for Y=3x or graph four
Suppose that the height (in centimeters) of a candle is a linear function of
the amount of time (in hours) it has been burning.
Let x be the amount of time in hours
Let y be the heoght of a candle in centimeters
The two points are then as (9,24.5) and (23,17.5).














Now plug in x=21, we get

Thus the height of the candle after 21 hours is 18.5 centimeters.
Answer:
The answer is "
"
Step-by-step explanation:
The whole question can be found in the file attached.

Subtracting the
from both sides of the equations:


Answer: x=1.5811389999999999 , or 1.59
Step-by-step explanation:
First, Subtract 20 from both sides.
12x2+20−20=50−20
12x2=30
Then, Divide both sides by 12:
12x^2/12 = 30/12
⇒ you get : x^2 = 5/2
After, Take square root.
x= ± √ 5/2
Finally you answer is going to be =1.5811389999999999 OR, 1.59
* Hopefully this helps:) Mark me the brainliest:)
<em>∞ 234483279c20∞</em>
1/2 plus 1/3 is 5/6.
You have to find the common denominator