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Westkost [7]
3 years ago
5

Enter an inequality that represents the phrase the sum of 1 and y is greater than or equal to 6. The inequality is y = 4 a solut

ion.
Mathematics
1 answer:
True [87]3 years ago
3 0

Answer:

Inequality to represent given data is y ≥ 5.

No, y = 4 is not a solution, since 4 is not a value that falls within the domain of the solutions for the inequality.

Step-by-step explanation:

Enter an inequality that represents the phrase the sum of 1 and y is greater than or equal to 6. The inequality is y = 4 a solution.

i) therefore y + 1 ≥ 6

ii) therefore y ≥ 5

iii) No, y = 4 is not a solution, since 4 is not a value that falls within the domain of the solutions for the inequality.

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Can someone please help me with these two parts
alex41 [277]
7a) do 400 take 24 to get 376 then divide that by 4
376 ÷ 4 = 94

so you can fit 94 railroad cars
3 0
3 years ago
A coin is tossed 3 times. what is the probability of obtaning two heads out of the 3 tosses
Nataly [62]
I answered a similar problem yesterday.
In three coin tosses there are 8 possible outcomes:
H H H
H H T
H T H
T H H
T T H
T H T
H T T
T T T

Of those results, four out of the eight have at least 2 tails and so the probability is (4/8) or50%

If you need the probability of getting EXACTLY 2 tails then the probability is (3/8) or .375


3 0
3 years ago
the cylinder has radius 4√3 and hight h. the total surface area of the cylinder is 56π√6. find the exact value of h giving the a
Arte-miy333 [17]

The area of the cylinder is a function of its height (h) and radius, (\mathbf{4\sqrt 3})

The exact value of h is: \mathbf{7\sqrt 2- 4\sqrt 3}

The given parameters are:

\mathbf{Area =56\pi\sqrt 6}

\mathbf{r=4\sqrt 3}

The surface area of a cylinder is calculated as:

\mathbf{Area = 2\pi rh + 2\pi r^2}

Substitute values for Area

\mathbf{56\pi\sqrt 6= 2\pi rh + 2\pi r^2}

Divide through by pi

\mathbf{56\sqrt 6= 2 rh + 2r^2}

Substitute value for r

\mathbf{56\sqrt 6= 2 (4\sqrt 3)h + 2(4\sqrt 3)^2}

\mathbf{56\sqrt 6= 8h\sqrt 3 + 2\times 48}

\mathbf{56\sqrt 6= 8h\sqrt 3 + 96}

Collect like terms

\mathbf{8h\sqrt 3 = 56\sqrt 6- 96}

Make h the subject

\mathbf{h = \frac{56\sqrt 6}{8\sqrt 3}- \frac{96}{8\sqrt 3}}

\mathbf{h = 7\sqrt 2- \frac{12}{\sqrt 3}}

Rationalize

\mathbf{h = 7\sqrt 2- \frac{12\sqrt 3}{3}}

\mathbf{h = 7\sqrt 2- 4\sqrt 3}

Hence, the exact value of h is: \mathbf{7\sqrt 2- 4\sqrt 3}

Read more about surface areas t:

brainly.com/question/25131428

5 0
2 years ago
(12) In a relay race, Mia ran 1.43 kilometers. Then she passed the baton to Gerald, who ran an
BigorU [14]

Answer:

4.13

Step-by-step explanation:

To find out how many kilometres they ran in all you have to do 1.43+2.7 =4.13

3 0
3 years ago
Read 2 more answers
Graph the system of equations.
Marat540 [252]
You can soustracte the first or the second one

and y cancel

x = 6

now you put 6 in x
you can take the first or the second one

6 - y = -2
6 - y = -2
y = -8
8 0
3 years ago
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