Answer:
Here we have the relation:
m = 140*h
Where m is the distance in miles, and h is time in hours.
And we want to complete a table like:
![\left[\begin{array}{ccc}in, h&out, m\\&\\&\\&\\&\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Din%2C%20h%26out%2C%20m%5C%5C%26%5C%5C%26%5C%5C%26%5C%5C%26%5Cend%7Barray%7D%5Cright%5D)
The way to complete this, is to evaluate the function:
m = 140*h
in different values of h, and then record both values of h and m in the table.
Let's use values of h that increase by 0.5, then:
if h = 0.5
m = 140*0.5 = 70
We have the pair: h = 0.5, m = 70
if h = 1
m = 140*1 = 140
We have the pair: h = 1, m = 140
if h = 1.5
m = 140*1.5 = 210
Then we have the pair h = 1.5, m = 210
if h = 2
m = 140*2 = 280
We have the pair: h = 2, m = 280
Now we can complete the table, and it will be:
![\left[\begin{array}{ccc}in, h&out, m\\0.5&70\\1&140\\1.5&210\\2&280\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Din%2C%20h%26out%2C%20m%5C%5C0.5%2670%5C%5C1%26140%5C%5C1.5%26210%5C%5C2%26280%5Cend%7Barray%7D%5Cright%5D)
Answer:
Similarly, the distance between two points P1 = (x1,y1,z1) and P2 = (x2,y2,z2) in xyz-space is given by the following generalization of the distance formula, d(P1,P2) = (x2 x1)2 + (y2 y1)2 + (z2 z1)2. This can be proved by repeated application of the Pythagorean Theorem.
Step-by-step explanation:
Use a calculator
Answer:
The answer is C
Step-by-step explanation:
Let X and Y be two proportional quantities and let K be constant.
Y=KX so Y/X=K
So for Equation number 1 we have 4y=3x and we will fill it in for 4/3=K
solving to get 1.33...
Now repeat this for the rest to complete the chart
1- 1.33...
2. 1.6
3- 1.33...
4- 0.625
Now we can see that 1 and 3 are the same, so that's how you get your answer, hope this helps!
51=?
60 100
Then you cross-multiply the 51 and the 100 and get 5,100.
Next you take the 5,100 and divide it by the 60 which gives you your final answer of 85%.
It's an expression that can be simplified to read
( 0.7 x 0.4 ) ( b³ x b⁹ )
= ( 0.28 ) ( b¹² ) = 0.28 b¹² .
