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beks73 [17]
3 years ago
7

Observe the graph below. The graph shows a function that is asymptotic to

Mathematics
1 answer:
JulijaS [17]3 years ago
4 0
We have to see the graph to what the answer is. Sorry I wish I could help!
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Please come answer ASAP!!!<br> 5 - n divided by 3 = 4 what is the value of n?
Varvara68 [4.7K]

Hey there!

The equation we have been given is 5 - n/3 = -4.

Let's start by subtracting 5 from each side.

-n/3 = -9

Multiply each side by 3.

-n = -27

Multiply each side by -1.

n = 27

Check our answer.

5 - 27/3 = -4

5 - 9 = -4

-4 = -4

The value of n is 27.

Hope this helps!

7 0
3 years ago
What is the total cost of a $56.53 meal at a restaurant after including a 17% tip?
padilas [110]
The total cost is $66.14. Hope this helps.
7 0
3 years ago
What is x2 – 6 = 16x + 30 rewritten in standard form, then factored?
AlexFokin [52]

Answer:

The standard form of quadratic equation is x^2-16x-36=0

The factored form of x^2-16x-36=0 is (x+2)(x-18)=0

Step-by-step explanation:

Given equation x^2-6=16x+30

We have to write  in standard form and then factorize the given equation.

The standard form for a general quadratic equation is given as ax^2+bx+c=0

Consider x^2-6=16x+30

Taking all terms to left side, we have,

x^2-6-16x-30=0

Adding like terms, we have,

x^2-16x-36=0

Now we will factorize it.

We will solve the quadratic equation x^2-16x-36=0 using middle term splitting method,

-16x can be written as -18x+2x

x^2-16x-36=0  becomes

\Rightarrow x^2-18x+2x-36=0

Taking x common from first two terms  and 2 common from last two terms we have,

\Rightarrow x(x-18)+2(x-18)=0

\Rightarrow (x+2)(x-18)=0

Thus, the factored form of x^2-16x-36=0 is (x+2)(x-18)=0

4 0
3 years ago
Read 2 more answers
A psychological experiment was conducted to investigate the length of time (time delay) between the administration of a stimulus
aleksklad [387]

Answer:

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject H_0: \mu= 1.6, we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

The significance level for this test is 0.05.

Step-by-step explanation:

In this case, we want to prove if there is significant evidence that the mean differs from 1.6 seconds. That is the same as having evidence to reject the the hypothesis H_0:\mu= 1.6 (the null hypothesis always have the equal sign).

We have to test the null hypothesis

H_0:\mu= 1.6

The significance level for this test is 0.05

Calculation of the t-statistic:

t=\frac{M-\mu}{s/\sqrt{n}} =\frac{2.2-1.6}{0.57/\sqrt{36}} =\frac{0.6}{0.063}= 9.47

If we look up in a t-table for t=9.47 and df=(36-1)=35, we get this value appears with a probability of zero. A large number like that is very unlikely to happen.

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject H_0: \mu= 1.6, we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

6 0
3 years ago
In the diagram below DE is parallel to XY. What is the value of y?
kirza4 [7]

this would be 94 hope it helps

3 0
3 years ago
Read 2 more answers
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