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4 years ago

Are these answers correct?

Mathematics

2 answers:

Mars2501 [29]4 years ago

7 0

Very good job! They are all correct and it shows how you got the answer! ^_^ 100%

kherson [118]4 years ago

4 0

All of them is correct very good job

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Please help me with this!

stira [4]

Answer:

Step-by-step explanation:

Its going to be a negative

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3 years ago

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If angle 2 is 74 degrees, what is angle 7?

mojhsa [17]

Answer:

106

Step-by-step explanation:

Depending on the angle it has to equal 180

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4 years ago

Find dy/dx for 4 - xy = y^3

storchak [24]

Answer:

$\frac{dy}{dx}=-\frac{y}{3y^2+x}$

Step-by-step explanation:

4-xy=y^3

dy/dx=?

$\frac{d(4-xy)}{dx}=\frac{d(y^3)}{dx}\\ \frac{d(4)}{dx}-\frac{d(xy)}{dx}=3y^{3-1}\frac{dy}{dx}\\ 0-(\frac{dx}{dx}y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -(1y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -(y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -y-x\frac{dy}{dx}=3y^2\frac{dy}{dx}$

Solving for dy/dx: Addind x dy/dx both sides of the equation:

$-y-x\frac{dy}{dx}+x\frac{dy}{dx}=3y^2\frac{dy}{dx}+x\frac{dy}{dx} \\ -y=3y^2\frac{dy}{dx}+x\frac{dy}{dx}$

Common factor dy/dx on the right side of the equation:

$-y=(3y^2+x)\frac{dy}{dx}$

Dividing both sides of the equation by 3y^2+x:

$\frac{-y}{3y^2+x}=\frac{(3y^2+x)}{3y^2+x}\frac{dy}{dx}\\ -\frac{y}{3y^2+x}=\frac{dy}{dx}\\ \frac{dy}{dx}=-\frac{y}{3y^2+x}$

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3 years ago

!!!BRAINY AND 10 PTS!!!

Dovator [93]

Answer:

its the 2nd on on the top row

Step-by-step explanation:

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3 years ago

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What are the vertical asymptotes of the function f(x) = the quantity of 3x plus 9, all over x squared plus 4x minus 12?

Zinaida [17]

In order to find the vertical asymptotes of a rational function you must set the denominator = 0 and solve for x.

If F(x) = (3x + 9) / (x^2 + 4x - 12), then set x^2 + 4x - 12 = 0 and solve for x.

(x + 6)(x - 2) = 0

x + 6 = 0 so then x = -6
x - 2 = 0 so then x = 2

For this particular function, you have 2 vertical asymptotes. x = -6 and x = 2

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3 years ago

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