Factor the expression completely over the complex numbers.
x^3-4x^2+4x-16
1 answer:
First you must know that is i∧2= -1
x∧3-4x∧2+4x-16 = x∧2 (x-4) + 4 (x-4) = (x-4) (x∧2+4) = (x-4) (x∧2-(-4)) =
= (x-4) (x∧2-(-1) *4) = (x-4) (x∧2- i∧2*2∧2) = (x-4) (x∧2-(2i)∧2) = (x-4) (x-2i) (x+2i)
Good luck!!!
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