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Paul [167]
3 years ago
6

What are two numbers that add to three and multiply to two

Mathematics
2 answers:
Mice21 [21]3 years ago
8 0
1 and 2
because you can do the math and it works:
1+2=3
1*2=2
sladkih [1.3K]3 years ago
6 0
1 and 2 because 1+2=3.Also 1×2=2.
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In a house, there is a small statue in the shape of a cylinder. The cylinder has a diameter of 8 inches and a height of h inches
Kitty [74]

The equation that best represent the volume of the cylinder in cubic inches is V = π4²h.

<h3>What is a cylinder?</h3>

A cylinder is simply a 3-dimensional shape having two parallel circular bases joined by a curved surface.

The volume of a cylinder is expressed as;

V = π × r² × h

Where r is radius of the circular base, h is height and π is constant pi.

Given that;

  • Diameter d = 8in
  • Radius r = d/2 = 8in/2 = 4in
  • Height = h
  • Volume of the cylinder V = ?

V = π × r² × h

V = π × (4)² × h

V = π4²h

Therefore, the equation that best represent the volume of the cylinder in cubic inches is V = π4²h.

Learn more on volume of cylinder here: brainly.com/question/16788902

#SPJ1

3 0
2 years ago
(-x+3)-(x-5)=2x+8 how
Iteru [2.4K]

Answer:

x=4

Step-by-step explanation:

(-x+3)-(x-5)=2x+8

(-x+3)+(-x+5)=2x+8

-x+3-x+5=2x-8

-2x+8=2x-8

-2x-2x=-8-8

-4x=-16

x=-16/-4

x=4

8 0
3 years ago
Read 2 more answers
Expand the brackets 5(2x + 3)
zimovet [89]

Answer:

10x+15

Step-by-step explanation:

5 x 2x=10x

5x3=15

5 0
3 years ago
Read 2 more answers
When purchasing bulk orders of​ batteries, a toy manufacturer uses this acceptance sampling​ plan: Randomly select and test 56 b
nydimaria [60]

Answer:

98.1% chance of being accepted

Step-by-step explanation:

Given:

sample size,n=56

acceptance condition= at most 2 batteries do not meet specifications

shipment size=7000

battery percentage in shipment that do not meet specification= 1%

Applying binomial distribution

<h3>P(x)=∑ᵇₐ=₀ (n!/a!(n-a)!)p^a (1-p)^(n-a)</h3>

In this formula, a is the acceptable number of defectives;

 n is the sample size; 

p is the fraction of defectives in the population.  

Now putting the value

a= 2

n=56

p=0.01

\frac{56!}{0!\left(56-0\right)!}\left(0.01\right)^0\:\left(1-0.01\right)^{\left(56-0\right)} + \frac{56!}{1!\left(56-1\right)!}\left(0.01\right)^1\:\left(1-0.01\right)^{\left(56-1\right)} +\:\frac{56!}{2!\left(56-2\right)!}\left(0.01\right)^2\:\left(1-0.01\right)^{\left(56-2\right)}

=0.56960+0.32219+0.08949

After summation, we get 0.981 i.e. a 98.1% chance of being accepted.  As this is such a high chance, we can expect many of the shipments like this to be accepted!

7 0
3 years ago
Solve the problem. For large numbers of degrees of​ freedom, the critical chi χ squared 2 values can be approximated using the f
kykrilka [37]

Answer:

0.01  =0.0001

Step-by-step explanation:

7 0
3 years ago
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