Find the equation of the line parallel to y=-11-5, that passes through the point
2 answers:
Answer:
y=41−11x
Step-by-step explanation:
The equation of the line in the slope-intercept form is y=5−11x.
The slope of the parallel line is the same: m=−11.
So, the equation of the parallel line is y=−11x+a.
To find a, we use the fact that the line should pass through the given point: −3=(−11)⋅(4)+a.
Thus, a=41.
Therefore, the equation of the line is y=41−11x.
Answer:
y=41−11x
Step-by-step explanation:
The equation of the line in the slope-intercept form is y=5−11x.
The slope of the parallel line is the same: m=−11.
So, the equation of the parallel line is y=−11x+a.
To find a, we use the fact that the line should pass through the given point: −3=(−11)⋅(4)+a.
Thus, a=41.
Therefore, the equation of the line is y=41−11x.
Answer: y=41−11x.
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Brainliest? Thanks!
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There are 2 ways to turn a number into a percent...
(1) move the decimal 2 spaces to the right....0.3 = 30%
(2) multiply by 100....0.3 x 100 = 30%
Step-by-step explanation:
AC+CB+BA=180
2x+23+3x-8+4x+1=180
9x+16=180
9x=180-16
9x=164
x=164/9
x=18.2
The equation that matches the graph is the second one !
