Find the equation of the line parallel to y=-11-5, that passes through the point
2 answers:
Answer:
y=41−11x
Step-by-step explanation:
The equation of the line in the slope-intercept form is y=5−11x.
The slope of the parallel line is the same: m=−11.
So, the equation of the parallel line is y=−11x+a.
To find a, we use the fact that the line should pass through the given point: −3=(−11)⋅(4)+a.
Thus, a=41.
Therefore, the equation of the line is y=41−11x.
Answer:
y=41−11x
Step-by-step explanation:
The equation of the line in the slope-intercept form is y=5−11x.
The slope of the parallel line is the same: m=−11.
So, the equation of the parallel line is y=−11x+a.
To find a, we use the fact that the line should pass through the given point: −3=(−11)⋅(4)+a.
Thus, a=41.
Therefore, the equation of the line is y=41−11x.
Answer: y=41−11x.
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Answer:
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Step-by-step explanation:
Answer:
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