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3 years ago

Find the equation of the line parallel to y=-11-5, that passes through the point

Mathematics

2 answers:

Elanso [62]3 years ago

7 0

Answer:

y=41−11x

Step-by-step explanation:

The equation of the line in the slope-intercept form is y=5−11x.

The slope of the parallel line is the same: m=−11.

So, the equation of the parallel line is y=−11x+a.

To find a, we use the fact that the line should pass through the given point: −3=(−11)⋅(4)+a.

Thus, a=41.

Therefore, the equation of the line is y=41−11x.

RSB [31]3 years ago

3 0

Answer:

y=41−11x

Step-by-step explanation:

The equation of the line in the slope-intercept form is y=5−11x.

The slope of the parallel line is the same: m=−11.

So, the equation of the parallel line is y=−11x+a.

To find a, we use the fact that the line should pass through the given point: −3=(−11)⋅(4)+a.

Thus, a=41.

Therefore, the equation of the line is y=41−11x.

Answer: y=41−11x.

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