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arlik [135]
3 years ago
12

Line q will be graphed on the same grid. The only solution to the system of linear equations formed by lines n and q occurs when

x = 3/2 and y = 0. Which equation could represent line q?
Mathematics
1 answer:
bija089 [108]3 years ago
8 0

Answer:

f(x) = k(x - \frac{3}{2})

Step-by-step explanation:

Line q will be graphed on the same grid. The only solution to the system of linear equations formed by lines n and q occurs when x = \frac{3}{2} and y = 0.

Now, as x = \frac{3}{2}  is a solution of the equation, y = f(x) = 0, so, (x - \frac{3}{2}) will be a factor of the linear function y = f(x).

Therefore, we can write the possible equation for the line q will be

f(x) = k(x - \frac{3}{2}). (Where k is any constant} (Answer)

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Step-by-step explanation:

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Hope this helps! If it does, please mark me brainliest. Thank you! ;)

4 0
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Answer:

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Step-by-step explanation:

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7 0
2 years ago
Name the coefficient, base and power for each
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7 0
3 years ago
Can you help me create a polynomial function matching the criteria on the left please and thanks
Olenka [21]

Answer:

f(x) = \dfrac{1}{8}(x + 4)^2(x + 1)(x - 3)

Step-by-step explanation:

From inspection of the graph, we can see that the curve intercepts the x-axis at (-4, 0), (-1, 0) and (3, 0)

Therefore,

x = -4 ⇒ x + 4 = 0

x = -1 ⇒ x + 1 = 0

x = 3 ⇒ x - 3 = 0

Because (-4, 0) touches the x-axis, then (x + 4)² will be a factor

So (x + 4)², (x + 1) and (x - 3) are all factors of the polynomial

\implies f(x) = \dfrac{1}{n}(x + 4)^2(x + 1)(x - 3)

If we multiply the constants, this will give us the y-intercept:

⇒ 4² x 1 x -3 = -48

From inspection of the graph, the y-intercept is -6

So to get from -48 to -6 we need to multiply -48 by 1/8

Therefore, n = 1/8

\implies f(x) = \dfrac{1}{8}(x + 4)^2(x + 1)(x - 3)

7 0
2 years ago
Read 2 more answers
What is the answer > , <, or = -37/8______-4.63
Lunna [17]
-37/8 as a decimal is -4.625. So: -4.62 > -4.63
3 0
3 years ago
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