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disa [49]
3 years ago
10

A toll bridge charges $1.00 for passenger cars and $2.50 for other vehicles. suppose that during daytime hours, 60% of all vehic

les are passenger cars. if 25 vehicles cross the bridge during a particular daytime period, what is the resulting expected toll revenue? hint: let ???? = the number of passenger cars out of 25. start by identifying the type of discrete random variable ???? is. then, create a linear function of ???? to represent the toll revenue. finally, find the expected value of the function that represents the toll revenue.
Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
4 0
Number of passenger cars = 60% of 25
Number of passenger cars = 0.6 x 25
Number of passenger cars = 15

Number of Other Vehicles = 25 - 15
Number of Other Vehicles = 10

Revenue from passenger cars = $1.00 x 15
Revenue from passenger cars = $15.00

Revenue from Other Vehicles = $2.50 x 10
Revenue from Other Vehicles = $25.00

Total Revenue = $15.00 + $25.00
Total Revenue = $40.00

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Hey there!

Let's solve our equation below.

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Let's distribute the parentheses.

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If, when solving an equation, you get one number or variable that equals itself, there are infinitely many solutions.

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The answers to the bearing problems are listed below:

  1. How far North is the ship now ___________ 38.82 km
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<h3>Meaning of bearing.</h3>

Bearing can defined as branch of mathematics that describes the accurate location of an object at any point in time.

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A positive integer is twice another.the sum of the reciprocal of the two positive integer is 3/14. Find the integers
icang [17]

Answer:

\huge\boxed{14\ \text{and}\ 7}

Step-by-step explanation:

n,\ m-\text{positive integer}\\\\n=2m-\text{a positive integer is twice another}\\\\\dfrac{1}{n}+\dfrac{1}{m}=\dfrac{3}{14}-\text{the sum of the reciprocal of the two positive integer is }\ \dfrac{3}{14}\\\\\text{We have the system of equations:}\\\\\left\{\begin{array}{ccc}n=2m&(1)\\\dfrac{1}{n}+\dfrac{1}{m}=\dfrac{3}{14}&(2)\end{array}\right

\text{Substitute (1) to (2):}\\\\\dfrac{1}{2m}+\dfrac{1}{m}=\dfrac{3}{14}\\\\\dfrac{1}{2m}+\dfrac{1\cdot2}{m\cdot2}=\dfrac{3}{14}\\\\\dfrac{1}{2m}+\dfrac{2}{2m}=\dfrac{3}{14}\\\\\dfrac{1+2}{2m}=\dfrac{3}{14}\\\\\dfrac{3}{2m}=\dfrac{3}{14}\Rightarrow2m=14\qquad\text{divide both sides by 2}\\\\\dfrac{2m}{2}=\dfrac{14}{2}\\\\\boxed{m=7}

\text{Substitute it to (1):}\\\\n=2\cdot7\\\\\boxed{n=14}

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