So, to find the solution to this problem, we will we using pretty much the same method we used in your previous question. First, let's find the area of the rectangle. The area of a rectangle is length x width. The length in this problem is 16 and the width is 3, and after multiplying these together, we have found 48 in^2 to be the area of the square. Next, we can find the area of the trapezoid. The area of a trapezoid is ((a+b)/2)h where a is the first base, b is the second base, and h is the height. In this problem, a=16, b=5, and h=10. So, all we have to do is plug these values into the area formula. ((16+5)/2)10 = (21/2)10 = 105. So, the area of the trapezoid is 105 in^2. Now after adding the two areas together (48in^2 and 105in^2), we have found the solution to be 153in^2. I hope this helped! :)
Answer:
y=5x+7
Step-by-step explanation:
parallel lines have the same slope, but different y intercepts
y=5x+7
Well if you are solving for y
the answer is
Y= 4/5x- 3
if you are solving for x
the answer is
X=5/4y + 15/4
*look at the image for the work*
Answer:
x=36
Step-by-step explanation:
First rewrite equation then multiply each side by 36. 9x-36=4x+144.
then move the variable 9x-4x+36=144. Next subtract 9x and 4x ...5x=144+36.... 5x=180. Lastly you divide 180÷5 this your answer x=36
