Answer:
a. 8 years
b. $49.20
Step-by-step explanation:
The computation is shown below:
a. The mark age is
Given that
232 is 8 times of the sum of mark and his sister ages
And, his sister is 21
So,
Let us assume the mark age be x
now
8(x + 21) = 232
x + 21 = 29
x = 29 -21
x = 8
b. The original price of the socks is
As each pair get $3 off
And she bought 6 pairs for $31.20
= $31.20 + 6 × $3
= $31.20 + 18
= $49.20
So baically
reresent
s=number of studne tickes bouthgt
a=number of adult tickets bought
300 tickest sold
total=300
a+s=300
value=rate times number of peple
student value=4s
adults value=10a
total value=1950
4s+10a=1950
a. system of equations are
s+a=300
4s+10a=1950
b. solve
s+a=300
4s+10a=1950
a+s=300
multiply by -4
-4s-4a=-1200
add to other eqaution
4s+10a=1950
<u>-4s-4a=-1200 + </u>
0s+6a=750
6a=750
divide 6
a=125
subsiute
s+a=300
s+125=300
subtract 125
s=175
a. s+a=300
4s+10a=1950
b. solution above
175 students
125 aduls
Answer:
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Step-by-step explanation:
Answer:
y= -4
Step-by-step explanation:
The blue line is y=2 and the red is y= -4.
