for such experiment, you do it with care and to acquire and determine to put experience in it
Explanation:
because without you been or using experience the experiment will not correct
Answer:
A. 0
Explanation:
The technician should configure the RAID 0 for Joe.
RAID 0 also referred to as the striped volume or stripe set is configured to allow the fastest speed and the most storage capacity by splitting data evenly across multiple (at least two) disks, without redundancy and parity information.
Also, RAID 0 isn't fault tolerant, as failure of one drive will cause the entire array to fail thereby causing total data loss.
Answer:
C
Explanation:
Putting all government forms on the city web site is the least activity likely to be effective in the purpose of reducing digital divide.
Holding basic computer classes at the community centers will very much help to reduce the digital divide.
Providing free wireless internet connections at locations in low-income neighborhood will also reduce the gap of digital divide
Requiring that every city school has computers that meet a minimum hardware and software will made computing resources available to users thereby reducing digital divide.
Answer:
#include <iostream>
using namespace std;
int main()
{
string str;
cout<<"Enter the string: ";
cin>>str;
for(int i=0;str[i]!='\0';i++){
if(str[i]=='e'){
str[i]='x';
}
}
cout<<"the string is: "<<str<<endl;
return 0;
}
Explanation:
First, include the library iostream for using the input/output instructions.
Create the main function and declare the variables.
Then, use the cout instruction and print the message on the screen.
cin store the string enter by the user into a variable.
After that, take a for loop and if-else statement for checking the condition if the string contains the 'e', then change that alphabet to 'x'.
This process continues until the string not empty.
Finally, print the updated string.
Answer:
for (char outerChar='a'; outerChar<='e'; outerChar++){
for (char innerChar='a'; innerChar<='e'; innerChar++){
cout << outerChar << innerChar << "\n";
}
}