All categories

3 years ago

I'm having a very hard time with geometry and was hoping someone could help me, sorry i know this isn't exactly a question

Mathematics

1 answer:

natulia [17]3 years ago

6 0

Answer:

What kind of geometry EX. 6th grade 7th grade 8th grade Eureka etc.

Step-by-step explanation:

You might be interested in

Solve the inequality. 8≤-2x+16

alex41 [277]

Use photo math it will help

6 0

3 years ago

The length of a rectangular piece of land is 9 cm more than 3 times its width. The perimeter is 418 cm. Find its dimensions.

SashulF [63]

Let w represent the width of the rectangle in cm. Then its length in cm is (3w+9). The perimeter is the sum of two lengths and two widths, so is ...

... 418 = 2(w + (3w+9))

... 209 = 4w +9 . . . . . . divide by 2, collect terms

... 200 = 4w . . . . . . . . subtract 9

... 50 = w . . . . . . . . . . divide by 4

... length = 3w+9 = 3·50 +9 = 159

The dimensions of this piece of land are 159 cm by 50 cm.

3 0

3 years ago

LaTeX: \frac{4}{5}\times\frac{7}{10}\:=\:4 5 × 7 10 =

Gennadij [26K]

Is that even an actual equation?

7 0

2 years ago

Round to the nearest hundredth (Geometric Series problem)

WITCHER [35]

Answer:

15.98

Step-by-step explanation:

∑₁¹⁰ $8(\frac{1}{4} )^{n-1}$

$=8[1+\frac{1}{4} +\frac{1}{16} + ........ +t_{10}]$

We have to use the formula of sum of a G.P. series with common ratio r < 1.

If the first term is a, the common ratio is r and the number of terms is n then the sum [a + ar + ar² + ar³ + ......... up to n terms] is given by

$[a \times\frac{1-r^{n} }{1-r}]$

$= 8[1 \times \frac{1-\frac{1}{2^{10} } }{1-\frac{1}{2} } ]$

$= 15.98$ (Answer)

4 0

3 years ago

The volume of a rectangular prism is 2x^3 - 6x^2 + 8x , and the volume of a cube is 27x^3. What is the total volume of the prism

AleksAgata [21]

Answer:

$\displaystyle V_{P + C} = 29x^3 - 6x^2 + 8x$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify.

$\displaystyle V_P = 2x^3 - 6x^2 + 8x$

$\displaystyle V_C = 27x^3$

Step 2: Find Combined Volume

[Set up] Add: $\displaystyle V_P + V_C = V_{P + C}$
Substitute in variables: $\displaystyle V_{P + C} = 27x^3 + 2x^3 - 6x^2 + 8x$
Combine like terms: $\displaystyle V_{P + C} = 29x^3 - 6x^2 + 8x$

8 0

2 years ago