What are the x-intercepts of the circle (x – 3)2 + (y – 4)2 = 24?
2 answers:
X-intercept ⇒ When y = 0
(x – 3)² + (y – 4)²<span> = 24
When y = 0,
</span>(x – 3)² + (0 – 4)² = 24
(x – 3)² + 16 = 24
(x – 3)² = 8
(x - 3) = ±√8
x = √8 + 3 or x = -√8 + 3
x = (3 + 2√2) or (3- 2√2) [Radical Form]
x = 5.83 or 0.17 [Decimal Form]
Answer: (5.83, 0) and (0.17, 0)
(x-3)2+(y-4)2=24
2x-6+2y=24
2x-14+2y=24
2x=24+14-2y
2x=38-2y
x=19-y
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