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4 years ago

6

Dominick is training for a race. He spends 0.75 hours running each time he runs and 1.5 hours swimming each time he swims. This

week, he spent more than 6 hours training for the race. Which graph represents his possible training times this week? Image for option 1 Image for option 2 Image for option 3 Image for option 4

2 answers:

Finger [1]4 years ago

6 0

Answer:

The Answer Is A

Step-by-step explanation

For this case we define the variables:

X: Number of times Dominick runs per week

Y: Number of times that Dominick swims per week

If you spend more than 6h training per week, we have an inequality of the form

0.75x + 1.5y > 6

The set of inequality is given by the shaded region of the graph

ExtremeBDS [4]4 years ago

3 0

Answer:

The answer is "A"!

Step-by-step explanation:

0.75x + 1.5y> 6

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The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room.

Gelneren [198K]

Answer:

B. y² – 5y = 750

C. 750 – y(y – 5) = 0

E. (y + 25)(y – 30) = 0

I'm assuming the 2 in the second option is supposed to be an exponent.

Step-by-step explanation:

Length = y

Width = y-5

Length × Width = Area

Area = <u>y(y-5)</u> = 750

<u>Distribute.</u>

y²-5y=750 (B is correct)

<u>If you factor the equation above</u>

(y + 25)(y – 30) = 0 (E is correct)

Area = y(y-5) = 750

<u>Subtract y(y-5) from both sides.</u>

750-y(y-5) = 0 (C is correct)

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Angelina_Jolie [31]

Answer:

y = 2x + 11

Step-by-step explanation:

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goldenfox [79]

Answer:

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To isolate g, we do the same thing to both sides.

Dividing both sides by 25 gives us:

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3 years ago

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Tracy a teacher is and she's paid a monthly salary of $3,728 calculate her salary per annum

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Answer:

$44,736

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3 years ago

- Polynomial Functions -For each function, state the vertex; whether the vertex is a maximum or minimum point; the equation of t

vladimir2022 [97]

EXPLANATION

Given the function f(x) = (x-6)^2 + 1

$\mathrm{The\: vertex\: of\: an\: up-down\: facing\: parabola\: of\: the\: form}\: y=ax^2+bx+c\: \mathrm{is}\: x_v=-\frac{b}{2a}$

Expanding (x-6)^2 + 1 by applying the Perfect Square Formula:

$=x^2-12x+37$ $\mathrm{The\: parabola\: params\: are\colon}$ $a=1,\: b=-12,\: c=37$ $x_v=-\frac{b}{2a}$ $x_v=-\frac{\left(-12\right)}{2\cdot\:1}$ $\mathrm{Simplify}$ $x_v=6$ $y_v=6^2-12\cdot\: 6+37$

Simplify:

$y_v=1$

$\mathrm{Therefore\: the\: parabola\: vertex\: is}$ $\mleft(6,\: 1\mright)$ $\mathrm{If}\: a$ $\mathrm{If}\: a>0,\: \mathrm{then\: the\: vertex\: is\: a\: minimum\: value}$ $a=1$ $\mathrm{Minimum}\mleft(6,\: 1\mright)$ $\mathrm{For\: a\: parabola\: in\: standard\: form}\: y=ax^2+bx+c\: \mathrm{the\: axis\: of\: symmetry\: is\: the\: vertical\: line\: that\: goes\: through\: the\: vertex}\: x=\frac{-b}{2a}$

Expanding (x-6)^2 + 1 by applying the Perfect Square Formula:

$y=x^2-12x+37$ $\mathrm{Axis\: of\: Symmetry\: for}\: y=ax^2+bx+c\: \mathrm{is}\: x=\frac{-b}{2a}$ $a=1,\: b=-12$ $x=\frac{-\left(-12\right)}{2\cdot\:1}$ $\mathrm{Refine}$

Axis of simmetry : x=6

The quadratic function has the same shape than the parent function y=x^2 because there is NOT a coefficient within x.

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1 year ago