I: 12x-5y=0
II:(x+12)^2+(y-5)^2=169
with I:
12x=5y
x=(5/12)y
-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
(25/144)y^2+y^2+144+25=169
(25/144)y^2+y^2+169=169
(25/144)y^2+y^2=0
y^2=0
y=0
insert into I:
12x=0
x=0
-> only intersection is at (0,0) = option B
Answer:
7.56 km²
Step-by-step explanation:
Given data:
Width of the fjord, w = 6.3 km
Retreated terminus of the glacier between may 2001 and June 2005, d = 7.5 km
thus, the length lost , y = 7.5 - 6.3 = 1.2 km
now, the area is given as:
A = Length × width
on substituting the values, we get
A = 1.2 × 6.3
or
A = 7.56 km²
Hence, the surface area lost by the glacier in the fjord is 7.56 km²
The answer to (-5 × 2) 3 = -30.
Answer:
Jaden added instead of subtracting 23 and 5
Step-by-step explanation:
You see how these 2 angles marked are both inside the 2 parallel lines?
And they are on opposite side of the transversal, the line crossing the 2 parallel lines?
These 2 angles are alternate interior angles and they are equal, I think you can do the last part by yourself.
