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yulyashka [42]
2 years ago
8

HELP PLEASE ASAP!! (10 pts)

Mathematics
1 answer:
Mandarinka [93]2 years ago
8 0

Answer:

is there a question or picture?

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−3 2/3=x−1 1/4 pls help
slega [8]

Answer:

  • - 2 5/12

Step-by-step explanation:

  • −3 2/3 = x − 1 1/4
  • x = - 3 2/3 + 1 1/4
  • x = - 2 - 2/3 + 1/4
  • x = - 2 - 8/12 + 3/12
  • x = - 2 - 5/12
  • x = - 2 5/12
8 0
3 years ago
At what value of x does the graph of the following function f(x) have a vertical asymptote? f(x)=1/x+3
ratelena [41]

Answer:

d

Step-by-step explanation:

The denominator of f(x) cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

x + 3 = 0 ⇒ x = - 3 ← equation of vertical asymptote

5 0
4 years ago
Read 2 more answers
Square RSTU is translated to form R'S'T'U', which has vertices R'(–8, 1), S'(–4, 1), T'(–4, –3), and U'(–8, –3). If point S has
MrMuchimi

The answer to this question is C

8 0
3 years ago
Read 2 more answers
Solve the problem below
wlad13 [49]

Answer:

(5,0)

Step-by-step explanation:

an x-intercept is where the line crosses the x-axis. in this case it crosses it multiple time so other possible answers could be (1,0) or (-1,0)

6 0
3 years ago
Find the perimeter of the parallelogram with these vertices.
blondinia [14]

Check the picture below.

so we can say that two sides are "4" each in length, since opposite sides are equal, let's find how long the slanted sides are.

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[3 - (-4)]^2 + [5 - 2]^2}\implies d=\sqrt{(3+4)^2+3^2} \\\\\\ d=\sqrt{49+9}\implies d=\sqrt{58} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{4~~ + ~~4~~ + ~~\sqrt{58}~~ + ~~\sqrt{58}\implies 8+2\sqrt{58}}

4 0
3 years ago
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