Answer:
A
Step-by-step explanation:
vertical are always opposite each other
complementary are 180
supplementary are 90
4x+7=51
-7 - 7
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4x/4= 44/4=11
Audrey is eleven years old
Answer:
The chance that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses is P=0.0488.
Step-by-step explanation:
To solve this problem we divide the tossing in two: the first 5 tosses and the last 5 tosses.
Both heads and tails have an individual probability p=0.5.
Then, both group of five tosses have the same binomial distribution: n=5, p=0.5.
The probability that k heads are in the sample is:

Then, the probability that exactly 2 heads are among the first five tosses can be calculated as:

For the last five tosses, the probability that are exactly 4 heads is:

Then, the probability that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses can be calculated multypling the probabilities of these two independent events:

Y=18-7x/-4
gradient = 7/4
parallel lines, same gradient.
y--7=7/4(x-2)
y=7x-14-28/4
y= (7x + 14)/4
Answer:
As shown below
Step-by-step explanation:
Given that when X denotes the errors in an experimental transmission channel, when checked by a certifier that detects missing pulses. follows the cumulative density function as given below:

