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Ivan
3 years ago
9

The sum of two numbers is 24. if five times the smaller is added to twice the larger, the result is 78. find the two numbers

Mathematics
1 answer:
rewona [7]3 years ago
4 0
The value of small number is 10 and larger is 14



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Choose 1 answer:
tino4ka555 [31]

Answer:

A

Step-by-step explanation:

vertical are always opposite each other

complementary are 180

supplementary are 90

3 0
3 years ago
Read 2 more answers
Four times Audrey's age plus 7 is parag age. parag is 51. what is Audrey's age?
PSYCHO15rus [73]
4x+7=51
-7 - 7
--------------
4x/4= 44/4=11
Audrey is eleven years old
3 0
3 years ago
Read 2 more answers
a coin will be tossed 10 times. Find the chance that there will be exactly 2 heads among the first five tosses and exactly 4 hea
777dan777 [17]

Answer:

The chance that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses is P=0.0488.

Step-by-step explanation:

To solve this problem we divide the tossing in two: the first 5 tosses and the last 5 tosses.

Both heads and tails have an individual probability p=0.5.

Then, both group of five tosses have the same binomial distribution: n=5, p=0.5.

The probability that k heads are in the sample is:

P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{5}{k}\cdot0.5^k\cdot0.5^{5-k}

Then, the probability that exactly 2 heads are among the first five tosses can be calculated as:

P(x=2)=\dbinom{5}{2}\cdot0.5^{2}\cdot0.5^{3}=10\cdot0.25\cdot0.125=0.3125\\\\\\

For the last five tosses, the probability that are exactly 4 heads is:

P(x=4)=\dbinom{5}{4}\cdot0.5^{4}\cdot0.5^{1}=5\cdot0.0625\cdot0.5=0.1563\\\\\\

Then, the probability that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses can be calculated multypling the probabilities of these two independent events:

P(H_1=2;H_2=4)=P(H_1=2)\cdot P(H_2=4)=0.3125\cdot0.1563=0.0488

7 0
3 years ago
Write an equation in slope-intercept form for points through (2, -7), parallel to 7x - 4y = 18
pav-90 [236]
Y=18-7x/-4 
gradient = 7/4
parallel lines, same gradient.
y--7=7/4(x-2)
y=7x-14-28/4
y= (7x + 14)/4
6 0
3 years ago
Errors in an experimental transmission channel are found when thetransmission is checked by a certifier that detects missing pul
irina1246 [14]

Answer:

As shown below

Step-by-step explanation:

Given that when X denotes the errors in an experimental transmission channel, when checked by a certifier that detects missing pulses. follows the cumulative density function as given below:

F(x) = 0, 0

(a) P(X \leq  4) =F(4) = 0.9\\(b) P(X > 7)=1-F(8) = 0\\(c) P(X \leq  5)=F(6) = 0.9 \\(d) P(X> 4)=1-F(4)=1-0.9=0.1 \\(e) P(X \leq  2)=F(3) = 0.7

6 0
3 years ago
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