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3 years ago

What is the distance between the points (18, 39) and (3, 39) in the xy-plane?

Mathematics

1 answer:

nydimaria [60]3 years ago

8 0

Answer:

C. 15 units,

Step-by-step explanation:

The y coordinates are both 39 so the line joining the 2 points is a horizontal line.

Distance = 18-3 = 15.

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Read 2 more answers

The water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day.

valina [46]

Answer:

A sample of 179 is needed.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.85}{2} = 0.075$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.075 = 0.925$ , so Z = 1.44.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

A previous study found that for an average family the variance is 1.69 gallon?

This means that $\sigma = \sqrt{1.69} = 1.3$

If they are using a 85% level of confidence, how large of a sample is required to estimate the mean usage of water?

A sample of n is needed, and n is found for M = 0.14. So

$M = z\frac{\sigma}{\sqrt{n}}$

$0.14 = 1.44\frac{1.3}{\sqrt{n}}$

$0.14\sqrt{n} = 1.44*1.3$

$\sqrt{n} = \frac{1.44*1.3}{0.14}$

$(\sqrt{n})^2 = (\frac{1.44*1.3}{0.14})^2$

$n = 178.8$

Rounding up

A sample of 179 is needed.

7 0

3 years ago

If a cone has a volume of 338 cm^3 and a radius of 6 cm, how tall is it?

Anna35 [415]

The formula for the volume of a cone is V = πr²h ÷3

You are solving for the height, h.

V = 338 cm³ and r = 6 cm

338 = π(6)²h÷3

338 = π36h÷3

338 = π12h

28.16 = πh

8.965 = h

The height of the cone is around 9 cm.

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3 years ago

1. How many variables are involved in the chi-square test?

GarryVolchara [31]

The result of the respective questions are:

This chi-square test only takes into consideration one variable.
The type of chi-square test this is is a Goodness of Fit
df= 3
NO

<h3>How many variables are involved in the chi-square test?</h3>

This chi-square test only takes into consideration one variable.

The type of chi-square test this is, is a Goodness of Fit

To test the hypothesis, we must determine whether the actual data conform to the assumed distribution.

The "Goodness-of-Fit" test is a statistical hypothesis test that determines how well the data that was seen resembles the data that was predicted.

Parameter

n = 4

Therefore

Degrees of freedom

df= n - 1

df= 4 - 1

df= 3

In conclusion

Parameters

$\alpha = 0.05$

df = 3

Hence

Critical value = 7.814728

Test statistic = 6.6

Test statistic < Critical value, .

NO, the result of this test is not statistically significant.