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Zinaida [17]
3 years ago
13

if two objects at different temperatures are in contact with each other, what happens to their temperatures.

Physics
2 answers:
slava [35]3 years ago
3 0

Okay, let me reword this.  Heat flows to areas that are cool, however, once the heated area begins to cool, the other area begins to warm up. Then there comes a point when there is no energy being transmitted into the two areas. When that happens the two areas obtain/are at the same temperature.

For example, you let the warm are escape your kitchen and go into the cold garage. You leave the kitchen door open and the heat continues to flow into the cold garage. After a while you will begin to notice that the kitchen feels noticeably cooler and the garage feels somewhat warmer. Then you wait a while longer and realize that both of the rooms feel like they are at the same temperature. They have then reached equilibrium.

mestny [16]3 years ago
3 0
-- When the objects come in contact, heat energy begins to flow from the
warmer one to the cooler one. 

-- The warmer one cools as it loses heat energy, and the cooler one warms
as it gains heat energy. 

-- The flow of heat energy stops when the temperatures of both objects are equal.
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A 2.81 μF capacitor is charged to 1220 V and a 6.61 μF capacitor is charged to 560 V. These capacitors are then disconnected fro
fenix001 [56]

Answer:

756.88 Volts will be the potential difference across each capacitor.

Explanation:

Q=C\times V

Q = Charge on capacitor

C = Capacitance

V = Voltage across capacitor

Capacitance of first capacitor = C_1=2.81 \mu F=2.81\times 10^{-6} F

Charge of first capacitor = Q_1

Voltage across first capacitor = V_1=1220 V

Q_1=C_1V_1

Q_1=2.81\times 10^{-6} F\times 1220 V=0.0034282 C

Capacitance of first capacitor = C_2=6.61\mu F=6.61\times 10^{-6} F

Charge of second capacitor = Q_2

Voltage across first capacitor = V_2=560 V

Q_2=C_2V_2

Q_1=6.61\times 10^{-6} F\times 560 V=0.0037016 C

Both the capacitors are disconnected and positive plates are now connected to each other and the negative plates are connected to each other. These capacitors are connected in parallel combination.

Total charge = Q

Q =Q_1+Q_2=0.0034282 C+ 0.0037016 C=0.0071298 C

Total capacitance in parallel combination:

C_p=C_1+C_2=2.81\times 10^{-6} F+6.61\times 10^{-6} F=9.42\times 10^{-6} F

Potential across both capacitors = V

V=\frac{Q}{C}=\frac{0.0071298 C}{9.42\times 10^{-6} F}=756.88 V

756.88 Volts will be the potential difference across each capacitor.

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3 years ago
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Hoochie [10]

Answer

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Option B is the correct answer.

In a basketball game, a player shoots a jump shot then the floor pushes up on the player.

<h3>Newton's Third Law</h3>

Newton's third law states that when two bodies interact with each other, they apply forces to one another that are equal in magnitude and opposite in direction. The third law is also known as the law of action and reaction.

In the given situation, a player shoots a jump shot. It means that the player pushes the floor downward direction.

Newton's third law is applicable in this situation where the player pushes the floor downward direction, at the same time the floor pushes the player upward. The amount of force applied to the floor by the player is equal in magnitude and opposite in direction as compared to the force applied to the player by the floor.

Hence the option B is the correct answer.

To know more about Newton's third law, follow the link given below.

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