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ryzh [129]
3 years ago
14

When sugar or another substance is dissolved in water, it disappears from view and forms a homogeneous mixture with the water, a

lso called a solution.
If you can’t see the sugar, how can you tell that it is there?
Physics
1 answer:
adoni [48]3 years ago
6 0
You can tell if the sugar is still there by boiling off the water and leaving the sugar behind in the container. Sugar is a solid, and therefore cannot evaporate, so when the water reaches boiling point, it will evaporate at a quicker rate than before (water evaporates at any temperature in liquid form; just not enough to be noticeable) and leave the container to become water vapour
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Matter is made of small particles to small to be seen. Which of these best describe evidence of this statement? 1. Tara’s crayon
son4ous [18]

Answer:

Explanation:

I think the answer is statement no 3.

Hope it helps.

5 0
3 years ago
Read 2 more answers
In a football game the running back is running up the field. He starts from rest and runs 4 seconds with an acceleration of 1.3m
Amiraneli [1.4K]

Answer:

3.38m

Explanation:

Given parameters:

Time  = 4s

Acceleration  = 1.3m/s²

Unknown:

Magnitude of the displacement = ?

Solution:

The body starts at rest and the initial velocity is 0m/s. To solve this problem, we have to use the expression below;

    S   = Ut  + \frac{1}{2}at²

 S  = displacement

t is the time

  a is the acceleration

  U is the initial velocity

  V is the final velocity

Insert the parameters and solve;

   S = (0 x 4)  +  \frac{1}{2} x 1.3² x 4  = 3.38m

6 0
3 years ago
Two in-phase loudspeakers that emit sound with the same frequency are placed along a wall and are separated by a distance of 8.0
zloy xaker [14]

Answer: 278\ Hz

Explanation:

Given

Distance between two speakers is 8 m

Man is standing 12 away from the wall

When the person moves 3 parallel to the wall

the parallel distances from the speaker become 4+3, 4-3

Now, the difference of distances from the speaker is

\Delta d=\sqrt{12^2+(4+3)^2}-\sqrt{12^2-(4-3)^2}\\\Delta d=1.85\ m

Condition for destructive interference is

\Delta d=(2n-1)\dfrac{\lambda }{2}=(2n-1)\dfrac{\nu }{2f}\\\\\Rightarrow f=(2n-1)\dfrac{v}{2\Delta d}

for second destructive interference; n=2

\Rightarrow f=(2\times 2-1)\dfrac{343}{2\times 1.85}=278.10\approx 278\ Hz

4 0
3 years ago
A wheel rotates without friction about a stationary horizontal axis at the center of the wheel. A constant tangential force equa
charle [14.2K]
Find alpha from  ωf=ωi+αt
once you have it you can use: τ=Fr=89.0∗.1=Iα
to find I
3 0
4 years ago
Starting from a location with position vector r1,x =−17.5 m and r1,y=23.1 m , a rabbit hops around for 10.7 seconds with average
lawyer [7]

The kinematics of the uniform motion allows us to find the final position vector

           r = (-41.575 i + 42.253 j) m

Given parameters

  • the starting position x = -17.5 m y = 23.1 m
  • jump time t = 10.7 s
  • The average velocities vₓ = -2.25 m / s and v_y = 1.79 m / s

to find

  • the final position

The uniform motion occurs when the velocity of the bodies is constant, in this case the relationship can be used for each axis

               v = \frac{x-x_o}{t}

               x = x₀ + v t

Where vₓ it  is the velocity, x the displacement, x₀ the initial position and t the time

Let's set a reference system with the horizontal x-axis. Regarding which we carry out the measurements

X axis

we look for the final position

           x = x₀ + vₓ t

           x = -17.5 -2.25 10.7

           x = -41.575 m

Y Axis

we look for the final position

           y = y₀ + v_y t

           y = 23.1 + 1.79 10.7

          y = 42.253 m

In conclusion, using the kinematics of uniform motion, find the final position vector

           r = (-41.575 i + 42.253 j) m

learn more about uniform motion here:

brainly.com/question/17036013

3 0
3 years ago
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